मराठी

Integrate the function: 1-4x2

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प्रश्न

Integrate the function:

`sqrt(1- 4x^2)`

बेरीज
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उत्तर

`I = int sqrt(1 - 4x^2)` dx

`= 2 int sqrt(1/4 - x^2)` dx

`= 2 sqrt((1/2)^2 - x^2)` dx

`= 2 [x/2 sqrt((1/2)^2 - x^2) + 1/8  sin^-1  (x/(1//2))]  + C`

`= (xsqrt(1 - 4x^2))/2 + 1/4  sin^-1  (2x) + C`

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पाठ 7: Integrals - Exercise 7.7 [पृष्ठ ३३०]

APPEARS IN

एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
पाठ 7 Integrals
Exercise 7.7 | Q 2 | पृष्ठ ३३०

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