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Integrate the function: 1+3x-x2 - Mathematics

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प्रश्न

Integrate the function:

`sqrt(1+ 3x - x^2)`

बेरीज
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उत्तर

Let `I = int sqrt (1 + 3x - x^2) dx`

`= int sqrt (1 - (x^2 - 3x)) dx`

`= int sqrt (1 - (x^2 - 3x + 9/4) + 9/4)  dx`

`= int sqrt ((sqrt(13)/2)^2 - (x - 3/2)^2)  dx`

`= [(x - 3/2)/2* sqrt (13/4 - (x - 3/2)^2) + 13/8 sin^-1  ((x - 3/2)/(sqrt 13/2))] +C`                 `....[int sqrt (a^2 - x^2) dx = x/2 sqrt (a^2 - x^2) + a^2/2 sin^-1  x/a + C]`

`= (2x - 3)/4 sqrt (1 + 3x - x^2) + 13/8 sin^-1  ((2x - 3)/sqrt13) + C`

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पाठ 7: Integrals - Exercise 7.7 [पृष्ठ ३३०]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
पाठ 7 Integrals
Exercise 7.7 | Q 7 | पृष्ठ ३३०

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