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Integrate the function sec2xtan2x+4 - Mathematics

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प्रश्न

Integrate the function `(sec^2 x)/sqrt(tan^2 x + 4)`

बेरीज
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उत्तर

Let `I = int (sec^2 x)/sqrt(tan^2 x + 4)  dx`

Put tan x = t 

sec2 x dx = dt

Hence, `I = int dt/sqrt(t^2 + 4)  dt`

`= log abs ((t + sqrt(t^2 + 4))+ C`           `....[∵ int dx/sqrt (a^2 + x^2) = log |x + sqrt(x^2 + a^2)| + C]`

`= log abs (tan x + sqrt(tan^2 x + 4)) + C`

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पाठ 7: Integrals - Exercise 7.4 [पृष्ठ ३१५]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
पाठ 7 Integrals
Exercise 7.4 | Q 9 | पृष्ठ ३१५

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