मराठी

Integrate the function 19-25x2

Advertisements
Advertisements

प्रश्न

Integrate the function `1/sqrt(9 - 25x^2)`

बेरीज
Advertisements

उत्तर

Let `I = int dx/sqrt(9 - 25 x^2)`

`= 1/5 int dx/ (sqrt (9/25 - x^2))`

`= 1/5 int dx/ sqrt ((3/5)^2 - x^2)`

`1/5 sin^-1 (x /(3/5)) + C`           ....`[∵ int dx/sqrt (a^2 - x^2) = sin^-1  x/a + C]`

`= 1/5 sin^-1 ((5x)/3) + C`

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 7: Integrals - Exercise 7.4 [पृष्ठ ३१५]

APPEARS IN

एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
पाठ 7 Integrals
Exercise 7.4 | Q 4 | पृष्ठ ३१५

व्हिडिओ ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्‍न

Evaluate : ` int x^2/((x^2+4)(x^2+9))dx`


Find:

`int(x^3-1)/(x^3+x)dx`


Integrate the function `1/sqrt(1+4x^2)`


Integrate the function `(3x)/(1+ 2x^4)`


Integrate the function `x^2/(1 - x^6)`


Integrate the function `(x - 1)/sqrt(x^2 - 1)`


Integrate the function `x^2/sqrt(x^6 + a^6)`


Integrate the function `1/(9x^2 + 6x + 5)`


Integrate the function `1/sqrt(7 - 6x - x^2)`


Integrate the function `1/sqrt((x -1)(x - 2))`


Integrate the function `1/sqrt(8+3x  - x^2)`


Integrate the function `(4x+ 1)/sqrt(2x^2 + x - 3)`


Integrate the function `(x + 2)/sqrt(x^2 -1)`


Integrate the function `(6x + 7)/sqrt((x - 5)(x - 4))`


Integrate the function `(x + 2)/sqrt(4x - x^2)`


Integrate the function `(x+2)/sqrt(x^2 + 2x + 3)`


Integrate the function `(5x + 3)/sqrt(x^2 + 4x + 10)`


`int dx/sqrt(9x - 4x^2)` equals:


Integrate the function:

`sqrt(4 - x^2)`


Integrate the function:

`sqrt(1-4x - x^2)`


Integrate the function:

`sqrt(x^2 + 4x - 5)`


Integrate the function:

`sqrt(1+ 3x - x^2)`


`int sqrt(1+ x^2)  dx` is equal to ______.


Find `int dx/(5 - 8x - x^2)`


Find `int (2x)/(x^2 + 1)(x^2 + 2)^2 dx`


\[\int e^{ax} \text{ sin} \left( bx + C \right) dx\]

\[\int\text{ cos }\left( \text{ log x } \right) \text{ dx }\]

\[\int e^{2x} \cos^2 x\ dx\]

\[\int\frac{1}{\left( x^2 - 1 \right) \sqrt{x^2 + 1}} \text{ dx }\]

\[\int \left| x \right|^3 dx\] is equal to

\[\int\frac{8x + 13}{\sqrt{4x + 7}} \text{ dx }\]


If θ f(x) = `int_0^x t sin t  dt` then `f^1(x)` is


`int (a^x - b^x)^2/(a^xb^x)dx` equals ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×