मराठी

Integrate the function 19-25x2

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प्रश्न

Integrate the function `1/sqrt(9 - 25x^2)`

बेरीज
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उत्तर

Let `I = int dx/sqrt(9 - 25 x^2)`

`= 1/5 int dx/ (sqrt (9/25 - x^2))`

`= 1/5 int dx/ sqrt ((3/5)^2 - x^2)`

`1/5 sin^-1 (x /(3/5)) + C`           ....`[∵ int dx/sqrt (a^2 - x^2) = sin^-1  x/a + C]`

`= 1/5 sin^-1 ((5x)/3) + C`

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पाठ 7: Integrals - Exercise 7.4 [पृष्ठ ३१५]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
पाठ 7 Integrals
Exercise 7.4 | Q 4 | पृष्ठ ३१५

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