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प्रश्न
In the figure below, find the value of 'x'.
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उत्तर
In the right-angled triangle EDF,
∠D = 90°.
Hence, side EF is the hypotenuse.
According to Pythagoras' theorem,
l(EF)2 = l(ED)2 + l(DF)2
⇒ (17)2 = (x)2 + (8)2
⇒ 289 = x2 + 64
⇒ x2 = 289 − 64
⇒ x2 = 225
⇒ `root 225`
⇒ x = 15
∴ The value of x is 15.
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