Advertisements
Advertisements
प्रश्न
In ∆PQR, if ∠R > ∠Q, then ______.
पर्याय
QR > PR
PQ > PR
PQ < PR
QR < PR
Advertisements
उत्तर
In ∆PQR, if ∠R > ∠Q, then PQ > PR.
Explanation:
Given, ∠R > ∠Q
⇒ PQ > PR ...[Side opposite to greater angle is longer]
APPEARS IN
संबंधित प्रश्न
Determine the measure of each of the equal angles of a right-angled isosceles triangle.
Two lines AB and CD intersect at O such that BC is equal and parallel to AD. Prove that the lines AB and CD bisect at O.
In a ΔABC, if ∠A=l20° and AB = AC. Find ∠B and ∠C.
The vertical angle of an isosceles triangle is 100°. Find its base angles.
Prove that each angle of an equilateral triangle is 60°.
Fill the blank in the following so that the following statement is true.
Sides opposite to equal angles of a triangle are ......
Which of the following statements are true (T) and which are false (F)?
Sum of any two sides of a triangle is greater than twice the median drawn to the third side.
Which of the following statements are true (T) and which are false (F)?
If two angles of a triangle are unequal, then the greater angle has the larger side opposite to it.
Fill in the blank to make the following statement true.
If two sides of a triangle are unequal, then the larger side has .... angle opposite to it.
Write the sum of the angles of an obtuse triangle.
In the given figure, if AB ⊥ BC. then x =
In the given figure, if BP || CQ and AC = BC, then the measure of x is
In the given figure, if l1 || l2, the value of x is
In ∆ABC, AB = AC and ∠B = 50°. Then ∠C is equal to ______.
D is a point on the side BC of a ∆ABC such that AD bisects ∠BAC. Then ______.
In ∆PQR, ∠P = 70° and ∠R = 30°. Which side of this triangle is the longest? Give reason for your answer.
ABC is an isosceles triangle with AB = AC and D is a point on BC such that AD ⊥ BC (Figure). To prove that ∠BAD = ∠CAD, a student proceeded as follows:
In ∆ABD and ∆ACD,
AB = AC (Given)
∠B = ∠C (Because AB = AC)
and ∠ADB = ∠ADC
Therefore, ∆ABD ≅ ∆ACD (AAS)
So, ∠BAD = ∠CAD (CPCT)
What is the defect in the above arguments?
[Hint: Recall how ∠B = ∠C is proved when AB = AC].
Show that in a quadrilateral ABCD, AB + BC + CD + DA < 2(BD + AC)
Show that in a quadrilateral ABCD, AB + BC + CD + DA > AC + BD
