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प्रश्न
Fill the blank in the following so that the following statement is true.
Sides opposite to equal angles of a triangle are ......
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उत्तर
Sides opposite to equal angles of a triangle are equal
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संबंधित प्रश्न
The vertical angle of an isosceles triangle is 100°. Find its base angles.
Find the measure of each exterior angle of an equilateral triangle.
If the bisector of the exterior vertical angle of a triangle be parallel to the base. Show that the triangle is isosceles.
In an isosceles triangle, if the vertex angle is twice the sum of the base angles, calculate the angles of the triangle.
Fill the blank in the following so that the following statement is true.
Angle opposite to equal sides of a triangle are .....
In a ΔABC, if ∠B = ∠C = 45°, which is the longest side?
Which of the following statements are true (T) and which are false (F)?
If two angles of a triangle are unequal, then the greater angle has the larger side opposite to it.
In a triangle ABC, if AB = AC and AB is produced to D such that BD = BC, find ∠ACD: ∠ADC.
In the given figure, if AB ⊥ BC. then x =

In the given figure, for which value of x is l1 || l2?

The side BC of ΔABC is produced to a point D. The bisector of ∠A meets side BC in L. If ∠ABC = 30° and ∠ACD = 115°, then ∠ALC = ______.
In the given figure, if l1 || l2, the value of x is

Which of the following correctly describes the given triangle?
In ∆ABC, AB = AC and ∠B = 50°. Then ∠C is equal to ______.
In ∆PQR, if ∠R > ∠Q, then ______.
Is it possible to construct a triangle with lengths of its sides as 9 cm, 7 cm and 17 cm? Give reason for your answer.
Is it possible to construct a triangle with lengths of its sides as 8 cm, 7 cm and 4 cm? Give reason for your answer.
ABC is an isosceles triangle with AB = AC and D is a point on BC such that AD ⊥ BC (Figure). To prove that ∠BAD = ∠CAD, a student proceeded as follows:

In ∆ABD and ∆ACD,
AB = AC (Given)
∠B = ∠C (Because AB = AC)
and ∠ADB = ∠ADC
Therefore, ∆ABD ≅ ∆ACD (AAS)
So, ∠BAD = ∠CAD (CPCT)
What is the defect in the above arguments?
[Hint: Recall how ∠B = ∠C is proved when AB = AC].
