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प्रश्न
In the following figure RISK and CLUE are parallelograms. Find the measure of x.
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उत्तर
\[\text{ In the parallelogram RISK }: \]
\[\angle ISK + \angle RKS = 180° (\text{ sum of adjacent angles of a parallelogram is } 180°\]
\[\angle ISK = 180° - 120° = 60°\]
\[\text{ Similarly, in parallelogram CLUE }: \]
\[\angle CEU = \angle CLU = 70°(\text{ opposite angles of a parallelogram are equal })\]
\[\text{ In the triangle }: \]
\[x + \angle ISK + \angle CEU = 180°\]
\[x = 180° - \left( 70°+ 60° \right)\]
\[x = 180°- \left( 70°+ 60°\right) = 50°\]
संबंधित प्रश्न
Points E and F lie on diagonal AC of a parallelogram ABCD such that AE = CF. What type of quadrilateral is BFDE?
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It has all its sides of equal lengths.
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(i) Is ∆BOC ≅ ∆DOC? State the congruence condition used?
(ii) Also state, if ∠BCO = ∠DCO.
ABCD is a rhombus whose diagonals intersect at O. If AB = 10 cm, diagonal BD = 16 cm, find the length of diagonal AC.
Measure of one angle of a rhombus is 50°, find the measures of remaining three angles.
ABCD is a rhombus such that the perpendicular bisector of AB passes through D. Find the angles of the rhombus.
Hint: Join BD. Then ∆ABD is equilateral.
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