Advertisements
Advertisements
प्रश्न
In the following figure RISK and CLUE are parallelograms. Find the measure of x.
Advertisements
उत्तर
\[\text{ In the parallelogram RISK }: \]
\[\angle ISK + \angle RKS = 180° (\text{ sum of adjacent angles of a parallelogram is } 180°\]
\[\angle ISK = 180° - 120° = 60°\]
\[\text{ Similarly, in parallelogram CLUE }: \]
\[\angle CEU = \angle CLU = 70°(\text{ opposite angles of a parallelogram are equal })\]
\[\text{ In the triangle }: \]
\[x + \angle ISK + \angle CEU = 180°\]
\[x = 180° - \left( 70°+ 60° \right)\]
\[x = 180°- \left( 70°+ 60°\right) = 50°\]
संबंधित प्रश्न
The following figure is parallelogram. Find the degree values of the unknown x, y, z.
Two adjacent angles of a parallelogram are as 1 : 2. Find the measures of all the angles of the parallelogram.
Diagonals of parallelogram ABCD intersect at O as shown in the following fegure. XY contains O, and X, Y are points on opposite sides of the parallelogram. Give reasons for each of the following:
(i) OB = OD
(ii) ∠OBY = ∠ODX
(iii) ∠BOY = ∠DOX
(iv) ∆BOY ≅ ∆DOX
Now, state if XY is bisected at O.
Which of the following statement is true for a rhombus?
It can be a square.
The diagonals of a quadrilateral are perpendicular to each other. Is such a quadrilateral always a rhombus? If your answer is 'No', draw a figure to justify your answer.
If the diagonals of a rhombus are 12 cm and 16cm, find the length of each side.
Diagonals of a parallelogram intersect each other at point O. If AO = 5, BO = 12 and AB = 13 then show that `square`ABCD is a rhombus.
Draw a rhombus KLMN such that its side is 4 cm and m∠K = 75°.
ABCD is a rhombus. If ∠BCA = 35°. find ∠ADC.
If the diagonal of a rhombus are equal, then the rhombus is a
