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प्रश्न
ABCD is a rhombus and its diagonals intersect at O.
(i) Is ∆BOC ≅ ∆DOC? State the congruence condition used?
(ii) Also state, if ∠BCO = ∠DCO.
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उत्तर
(i) Yes
\[\text{ In } ∆ BCO \text{ and } ∆ DCO: \]
\[OC = OC (\text{ common })\]
\[BC = DC (\text{ all sides of a rhombus are equal })\]
\[BO = OD (\text{ diagonals of a rhomus bisect each other })\]
\[\text{ By SSS congruence }: \]
\[ ∆ BCO \cong ∆ DCO\]
Yes
By c.p.c.t:
\[\angle BCO = \angle DCO\]
संबंधित प्रश्न
The following figure is parallelogram. Find the degree values of the unknown x, y, z.
Diagonals of parallelogram ABCD intersect at O as shown in the following fegure. XY contains O, and X, Y are points on opposite sides of the parallelogram. Give reasons for each of the following:
(i) OB = OD
(ii) ∠OBY = ∠ODX
(iii) ∠BOY = ∠DOX
(iv) ∆BOY ≅ ∆DOX
Now, state if XY is bisected at O.
Which of the following statement is true for a rhombus?
Its diagonals are equal and perpendicular.
Fill in the blank, inthe following, so as to make the statement true:
A rhombus has all its sides of ...... length.
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Draw a rhombus, having each side of length 3.5 cm and one of the angles as 40°.
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Its diagonals are equal and bisect each other.
ABCD is a rhombus. If ∠BCA = 35°. find ∠ADC.
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