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प्रश्न
In a parallel plate capacitor with air between the plates, each plate has an area of 6 × 10−3m2 and the separation between the plates is 3 mm.
- Calculate the capacitance of the capacitor.
- If this capacitor is connected to 100 V supply, what would be the charge on each plate?
- How would charge on the plates be affected, if a 3 mm thick mica sheet of k = 6 is inserted between the plates while the voltage supply remains connected?
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उत्तर
Here, A = 6 × 10–3m2, d = 3 mm = 3 × 10–3m
- Capacitance, C = `(∈_0A)/d`
= `((8.85 xx 10^-12 xx 6 xx 10^-3))/(3 xx 10^-3)`
= 17.7 × 10–12F - Charge, Q = CV
= 17.7 × 10–12 × 100
= 17.7 × 10–10C - New charge Q' = KQ
= 6 × 17.7 × 10–10
= 1.062 × 10–8C
संबंधित प्रश्न
In a parallel plate capacitor with air between the plates, each plate has an area of 6 × 10−3 m2 and the distance between the plates is 3 mm. Calculate the capacitance of the capacitor. If this capacitor is connected to a 100 V supply, what is the charge on each plate of the capacitor?
The plates of a parallel plate capacitor have an area of 90 cm2 each and are separated by 2.5 mm. The capacitor is charged by connecting it to a 400 V supply.
(a) How much electrostatic energy is stored by the capacitor?
(b) View this energy as stored in the electrostatic field between the plates, and obtain the energy per unit volume u. Hence arrive at a relation between u and the magnitude of electric field E between the plates.
Solve the following question.
A parallel plate capacitor is charged by a battery to a potential difference V. It is disconnected from the battery and then connected to another uncharged capacitor of the same capacitance. Calculate the ratio of the energy stored in the combination to the initial energy on the single capacitor.
For a one dimensional electric field, the correct relation of E and potential V is _________.
For two plates separated by distance \[d\], what is the capacitance of a parallel plate capacitor without a dielectric medium?
What is the capacitance of a parallel plate capacitor with a dielectric medium of dielectric constant \[K\]?
What is the effect of increasing plate separation \[d\] on capacitance?
When a dielectric slab of dielectric constant \[K\] is inserted between the plates, what is the electric field \[E'\] due to polarisation of the dielectric?
When the electric field is reduced to \[E'=\frac{E}{K}\] by a dielectric, what happens to potential difference and capacitance?
In electronic circuits, what are filters and oscillators used for?
