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महाराष्ट्र राज्य शिक्षण मंडळएचएससी वाणिज्य (इंग्रजी माध्यम) इयत्ता १२ वी

If P01(L) = 40 and P01(P) = 90, find P01(D-B) and P01(F). - Mathematics and Statistics

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प्रश्न

If P01(L) = 40 and P01(P) = 90, find P01(D-B) and P01(F).

बेरीज
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उत्तर

Given, P01(L) = 40 and P01(P) = 90

Dorbish-Bowley’s Price Index Number

P01(D-B) = `("P"_01("L") + "P"_01("P"))/2`

= `(40 + 90)/2`

= `130/2`

= 65

Fisher’s Price Index Number

P01(F) = `sqrt("P"_01("L") xx "P"_01("P"))`

= `sqrt(40 xx 90)`

= `sqrt(3600)`

= 60`

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Construction of Index Numbers - Weighted Aggregate Method
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पाठ 2.5: Index Numbers - Q.4

संबंधित प्रश्‍न

If P01(L) = 90 and P01(P) = 40, find P01(D – B) and P01(F).


If ∑p0q0 = 140, ∑p0q1 = 200, ∑p1q0 = 350, ∑p1q1 = 460, find Laspeyre’s, Paasche’s, Dorbish-Bowley’s and Marshall-Edgeworth’s Price Index Numbers.


Find x in the following table if Laspeyre’s and Paasche’s Price Index Numbers are equal.

Commodity Base Year Current year
Price Quantity Price Quantity
A 2 10 2 5
B 2 5 x 2

If Laspeyre's Price Index Number is four times Paasche's Price Index Number, then find the relation between Dorbish-Bowley's and Fisher's Price Index Numbers.


Choose the correct alternative :

The price Index Number by Weighted Aggregate Method is given by ______.


Paasche’s Price Index Number is given by ______.


Choose the correct alternative :

Walsh’s Price Index Number is given by


Fill in the blank :

Paasche’s Price Index Number is given by _______.


Walsh’s Price Index Number is given by _______.


State whether the following is True or False :

`sum("p"_1"q"_1)/("p"_0"q"_1)` is Laspeyre’s Price Index Number.


State whether the following is True or False :

`(sum"p"_1"q"_0)/(sum"p"_0"q"_0) xx (sum"p"_1"q"_0)/(sum"p"_0"q"_0) xx 100` is Dorbish-Bowley’s Price Index Number.


Solve the following problem :

Calculate Dorbish-Bowley’s Price Index Number for the following data.

Commodity Base Year Current Year
  Price
p0
Quantity
q0
Price
p1
Quantity
q1
I 8 30 11 28
II 9 25 12 22
III 10 15 13 11

Find x if Laspeyre’s Price Index Number is same as Paasche’s Price Index Number for the following data

Commodity Base Year Current Year
  Price
p0
Quantity
q0
Price
p1
Quantity
q1
A 3 x 2 5
B 4 6 3 5

Solve the following problem :

Find x if Paasche’s Price Index Number is 140 for the following data.

Commodity Base Year Current Year
  Price
p0
Quantity
q0
Price
p1
Quantity
q1
A 20 8 40 7
B 50 10 60 10
C 40 15 60 x
D 12 15 15 15

If Laspeyre’s and Dorbish’s Price Index Numbers are 150.2 and 152.8 respectively, find Paasche’s Price Index Number.


Choose the correct alternative:

Price Index Number by using Weighted Aggregate Method is given by


Choose the correct alternative:

The formula P01 = `(sum"p"_1"q"_0)/(sum"p"_0"q"_0) xx 100` is for


Marshall-Edgeworth's Price Index Number is given by ______


The average of Laspeyre’s and Paasche’s Price Index Numbers is called ______ Price Index Number


Given P01(M-E) = 120, `sum"p"_1"q"_1` = 300, `sum"p"_0"q"_0` = 120, `sum"p"_0"q"_1` = 320, Find P01(L)


State whether the following statement is true or false:

Dorbish-Bowley's Price Index Number is the square root of the product of Laspeyre's and Paasche's Index Numbers.


Laspeyre’s Price Index Number uses current year’s quantities as weights.


If ∑ p0q0 = 120, ∑ p0q1 = 160, ∑ p1q1 = 140, ∑ p1qo = 200, find Laspeyre’s, Paasche’s, Dorbish-Bowley’s and Marshall-Edgeworth’s Price Index Numbers.


Complete the following activity to calculate, Laspeyre's and Paasche's Price Index Number for the following data :

Commodity Base Year Current Year
Price
p0
Quantity
q0
Price
p1
Quantity
q1
I 8 30 12 25
II 10 42 20 16

Solution:

Commodity Base Year Current Year p1q0 p0q0 p1q1 p0q1
  p0 q0 p1 q1
I 8 30 12 25 360 240 300 200
II 10 42 20 16 840 420 320 160
Total         `bb(sump_1q_0=1200)` `bb(sump_0q_0=660)` `bb(sump_1q_1=620)` `bb(sump_0q_1=360)`

Laspeyre's Price Index Number:

P01(L) = `(sum"p"_1"q"_0)/(sum"p"_0"q"_0) xx 100 = square/660xx100`

∴ P01(L) = `square`

Paasche 's Price Index Number:

P01(P) = `(sum"p"_1"q"_1)/(sum"p"_0"q"_1) xx 100=(620)/(square) xx 100`

∴ P01(P) = `square`


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