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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

How would you account for the irregular variation of ionization enthalpies (first and second) in the first series of the transition elements? - Chemistry

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प्रश्न

How would you account for the irregular variation of ionization enthalpies (first and second) in the first series of the transition elements?

लघु उत्तर
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उत्तर १

Ionization enthalpies are found to increase in the given series due to a continuous filling of the inner d-orbitals. The irregular variations of ionization enthalpies can be attributed to the extra stability of configurations such as d0, d5 and d10. Since these states are exceptionally stable, their ionization enthalpies are very high.

In terms of first ionization energy, Cr has low ionization energy. This is because after losing one electron, it attains the stable configuration (3d5). On the other hand, Zn has exceptionally high first ionization energy, as an electron has to be removed from stable and fully-filled orbitals (3d10 4s2).

The second ionization energies are higher than the first since it becomes difficult to remove an electron when an electron has already been removed. Also, elements like Cr and Cu have exceptionally high second ionization energies, as after losing the first electron, they have attained the stable configuration (Cr+: 3d5 and Cu+: 3d10). Hence, taking out one electron more from this stable configuration will require a lot of energy.

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उत्तर २

The irregular variations in ionization enthalpy are due to differences in the stability of different 3d configurations (e.g., d0, d5, d10 are unusually stable).

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पाठ 4: The d-block and f-block Elements - Intext Question [पृष्ठ १००]

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एनसीईआरटी Chemistry Part 1 and 2 [English] Class 12
पाठ 4 The d-block and f-block Elements
Intext Question | Q 4.5 | पृष्ठ १००

संबंधित प्रश्‍न

Why do interstitial compounds have higher melting points than corresponding pure metals?


Account for the following: 

Cr2+ is a strong reducing agent.


The elements of 3d transition series are given as: Sc Ti V Cr Mn Fe Co

Answer the following: Write the element which shows maximum number of oxidation states. Give reason.


Out of Mn3+ and Cr3+, which is more paramagnetic and why ?

(Atomic nos. : Mn = 25, Cr = 24)


What are the characteristics of the transition elements and why are they called transition elements? 


Describe the oxidising action of potassium dichromate and write the ionic equation for its reaction with iodide.


For M2+/M and M3+/M2+ systems, the EΘ values for some metals are as follows:

Cr2+/Cr −0.9 V
Mn2+/Mn −1.2 V
Fe2+/Fe −0.4 V
Cr3/Cr2+ −0.4 V
Mn3+/Mn2+ +1.5 V
Fe3+/Fe2+ +0.8 V

Use this data to comment upon:

The stability of Fe3+ in acid solution as compared to that of Cr3+ or Mn3+.


Which one of the following ions is coloured?


Following are the transition metal ions of 3d series:

Ti4+, V2+, Mn3+, Cr3+

(Atomic numbers: Ti = 22, V = 23, Mn = 25, Cr = 24)

Answer the following:

1) Which ion is most stable in an aqueous solution and why?

2) Which ion is a strong oxidising agent and why?

3) Which ion is colourless and why?


Explain why Mn2+ is more stable than Fe2+ towards oxidation to +3 state. (At. no. of Mn = 25, Fe = 26)


The magnetic moment is associated with its spin angular momentum and orbital angular momentum. Spin only magnetic moment value of \[\ce{Cr^{3+}}\] ion is ______.


Assertion: The highest oxidation state of osmium is +8.

Reason: Osmium is a 5d-block element.


When an oxide of manganese (A) is fused with KOH in the presence of an oxidising agent and dissolved in water, it gives a dark green solution of compound (B). Compound (B) disproportionates in neutral or acidic solution to give purple compound (C). An alkaline solution of compound (C) oxidises potassium iodide solution to a compound (D) and compound (A) is also formed. Identify compounds A to D and also explain the reactions involved.


The element with atomic number 46 belongs to


Agcl is soluble in NH4OH. The solubility is due to the information of:-


Give reasons for the following statement:

Zn, Cd, and Hg are soft metals.


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Which of the following ions has the electronic configuration 3d6?
(Atomic number: Mn = 25, Co = 27, Ni = 28)


Consider the following standard electrode potential values:

\[\ce{Sn^{2+}_{ (aq)} + 2e^- -> Sn_{(s)}}\]; E0 = −0.14 V

\[\ce{Fe^{3+}_{ (aq)} + e^- -> Fe^{2+}_{ (aq)}}\]; E0 = +0.77 V

What is the cell reaction and potential for the spontaneous reaction that occurs?


Give a reason for the following.

Some transition metals and their compounds get attracted towards the magnetic field.


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