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प्रश्न
Why is the `"E"_(("V"^(3+)//"V"^(2+)))^"o"` value for vanadium comparatively low?
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उत्तर
The low value for V is related to the stability of V2+ (half-filled t2g level).
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संबंधित प्रश्न
The elements of 3d transition series are given as: Sc Ti V Cr Mn Fe Co
Answer the following: Write the element which shows maximum number of oxidation states. Give reason.
Explain briefly how +2 state becomes more and more stable in the first half of the first row transition elements with increasing atomic number?
How would you account for the following:
Of the d4 species, Cr2+ is strongly reducing while manganese (III) is strongly oxidising.
Electronic configuration of a transition element X in +3 oxidation state is [Ar]3d5. What is its atomic number?
Identify the metal and justify your answer.
Carbonyl \[\ce{M(CO)5}\]
Mention the type of compounds formed when small atoms like H, C and N get trapped inside the crystal lattice of transition metals. Also give physical and chemical characteristics of these compounds.
Which one among the following metals of the 3d series has the lowest melting point?
Assertion (A): Transition metals show their highest oxidation state with oxygen.
Reason (R): The ability of oxygen to form multiple bonds to metals.
Write the ionic equation for reaction of KI with acidified KMnO4.
Match List-I with List-II.
| List-I | List-II |
| A. Haber process | I. Fe catalyst |
| B. Wacker oxidation | II. PdCl2 |
| C. Wilkinson catalyst | III. [(PPh3)3RhCl] |
| D. Ziegler catalyst | IV. TiCl4 with Al(CH3)3 |
Choose the correct answer from the options given below:
