Advertisements
Advertisements
प्रश्न
Find the Pythagorean triplet from among the following set of numbers.
2, 6, 7
Advertisements
उत्तर
It is known that, if in a triplet of natural numbers, the square of the biggest number is equal to the sum of the squares of the other two numbers, then the three numbers form a Pythagorean triplet.
The given set of numbers is (2, 6, 7).
The biggest number among the given set is 7.
72 = 49; 62 = 36; 22 = 4
Now, 4 + 36 = 40 ≠ 49
∴ 22 + 62 ≠ 72
Thus, (2, 6, 7) does not form a Pythagorean triplet.
संबंधित प्रश्न
The perpendicular AD on the base BC of a ∆ABC intersects BC at D so that DB = 3 CD. Prove that `2"AB"^2 = 2"AC"^2 + "BC"^2`
In the given figure, point T is in the interior of rectangle PQRS, Prove that, TS2 + TQ2 = TP2 + TR2 (As shown in the figure, draw seg AB || side SR and A-T-B)
In the figure: ∠PSQ = 90o, PQ = 10 cm, QS = 6 cm and RQ = 9 cm. Calculate the length of PR.
In triangle PQR, angle Q = 90°, find: PQ, if PR = 34 cm and QR = 30 cm
A man goes 10 m due east and then 24 m due north. Find the distance from the straight point.
A right triangle has hypotenuse p cm and one side q cm. If p - q = 1, find the length of third side of the triangle.
Each side of rhombus is 10cm. If one of its diagonals is 16cm, find the length of the other diagonals.
In a triangle ABC, AC > AB, D is the midpoint BC, and AE ⊥ BC. Prove that: AB2 + AC2 = 2AD2 + `(1)/(2)"BC"^2`
AD is perpendicular to the side BC of an equilateral ΔABC. Prove that 4AD2 = 3AB2.
A right-angled triangle may have all sides equal.
