Question

A man goes 10 m due east and then 24 m due north. Find the distance from the straight point.

Answer 1

Let O be the original position of the man.
From the figure, it is clear that B is the final position of the man.
ΔAOB is right-angled at A.
By Pythagoras theorem,
OB² = OA² + AB²
OB² = (10m)² + (24m)²
OB² = 100m² + 576m²
OB² = 676m²
OB² = (26m)²
OB = 26m
Thus, the man is at a distance of 26m from the straight point.