Advertisements
Advertisements
प्रश्न
Find the area of quadrilateral BCEG
Advertisements
उत्तर
Area of the Quadrilateral BCEG = `1/2 [(x_1y_2 + x_2y_3 + x_3y_4 + x_4y_1) - (x_2y_1 + x_3y_2 + x_4y_3 + x_1y_4)]`
= `1/2[(4 + 2 + 0.75 + 9) - (-4 - 1.5 - 4.5 - 2)]`
= `1/2[15.75 + 12]`
= `1/2 [27.75]`
= 13.875
= 13.88 sq. units
APPEARS IN
संबंधित प्रश्न
The distance between parallel sides of a trapezium is 15 cm and the length of the line segment joining the mid-points of its non-parallel sides is 26 cm. Find the area of the trapezium.
ABCD is a square with each side 12 cm. P is a point on BC such that area of ΔABP: area of trapezium APCD = 1: 5. Find the length of CP.
The area of a rectangular is 640 m2. Taking its length as x cm; find in terms of x, the width of the rectangle. If the perimeter of the rectangle is 104 m; find its dimensions.
Trapezium given below; find its area.
The cost of enclosing a rectangular garden with a fence all around, at the rate of 75 paise per metre, is Rs. 300. If the length of the garden is 120 metres, find the area of the field in square metres.
The perimeter of a rhombus is 52 cm. If one diagonal is 24 cm; find:
(i) The length of its other diagonal,
(ii) Its area.
The diagram, given below, shows two paths drawn inside a rectangular field 80 m long and 45 m wide. The widths of the two paths are 8 m and 15 m as shown. Find the area of the shaded portion.
Sum of the areas of two squares is 400 cm2. If the difference of their perimeters is 16 cm, find the sides of the two squares.
Find the area of the quadrilateral whose vertices are at (– 9, – 2), (– 8, – 4), (2, 2) and (1, – 3)
The quadrilateral swimming pool shown is surrounded by concrete patio. Find the area of the patio
