मराठी
कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान इयत्ता ११

Explain the following: Electron gain enthalpy of chlorine is more negative as compared to fluorine.

Advertisements
Advertisements

प्रश्न

Explain the following:

Electron gain enthalpy of chlorine is more negative as compared to fluorine.

टीपा लिहा
Advertisements

उत्तर

Due to small size, the electron-electron repulsions in the relatively compact 2p-subshell of F are quite strong and hence the incoming electron is not accepted with the same ease as in case of bigger Cl atom where repulsions are comparatively weak. Thus, electron gain enthalpy of chlorine is more negative as compared to that of fluorine.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 11: The p-block Elements - Multiple Choice Questions (Type - I) [पृष्ठ १३८]

APPEARS IN

एनसीईआरटी एक्झांप्लर Chemistry Exemplar [English] Class 11
पाठ 11 The p-block Elements
Multiple Choice Questions (Type - I) | Q 33.(vi) | पृष्ठ १३८

संबंधित प्रश्‍न

Suggest reasons why the B–F bond lengths in BF3 (130 pm) and `"BF"_4^(-)` (143 pm) differ.


How would you explain the lower atomic radius of Ga as compared to Al?


In some of the reactions thallium resembles aluminium, whereas in others it resembles with group I metals. Support this statement by giving some evidences.


What do you understand by inert pair effect?


The geometry of a complex species can be understood from the knowledge of type of hybridisation of orbitals of central atom. The hybridisation of orbitals of central atom in [Be(OH)4]– and the geometry of the complex are respectively.


Which of the following oxides is acidic in nature?


In the structure of diborane ______.


Which of the following statements are correct. Answer on the basis of Figure.

(i) The two birdged hydrogen atoms and the two boron atoms lie in one plane;

(ii) Out of six B – H bonds two bonds can be described in terms of 3 centre 2-electron bonds.

(iii) Out of six B – H bonds four B – H bonds can be described in terms of 3 centre 2 electron bonds;

(iv) The four-terminal B – H bonds are two centre-two electron regular bonds.


Aluminium dissolves in mineral acids and aqueous alkalies and thus shows amphoteric character. A piece of aluminium foil is treated with dilute hydrochloric acid or dilute sodium hydroxide solution in a test tube and on bringing a burning matchstick near the mouth of the test tube, a pop sound indicates the evolution of hydrogen gas. The same activity when performed with concentrated nitric acid, reaction doesn’t proceed. Explain the reason.


Explain the following:

Tl (NO3)3 acts as an oxidising agent.


Match the species given in Column I with properties given in Column II.

Column I Column II
(i) Diborane (a) Used as a flux for soldering metals
(ii) Galluim (b) Crystalline form of silica
(iii) Borax (c) Banana bonds
(iv) Aluminosilicate (d) Low melting, high boiling, useful for measuring high temperatures
(v) Quartz (e) Used as catalyst in petrochemical industries

Describe the general trends in the following properties of the elements in Groups 13 and 14.

Metallic character


Account for the following observations:

Though fluorine is more electronegative than chlorine yet BF3 is a weaker Lewis acid than BCl3 


Account for the following observations:

PbO2 is a stronger oxidising agent than SnO2 


Three pairs of compounds are given below. Identify that compound in each of the pairs which has group 13 element in more stable oxidation state. Give reason for your choice. State the nature of bonding also.

AlCl3 , AlCl


Boron compounds behave as Lewis acids because of their ______.


A group 13 element ‘X’ reacts with chlorine gas to produce a compound XCl3. XCl3 is electron deficient and easily reacts with NH3 to form \[\ce{Cl3X –> NH3}\] adduct; however, XCl3 does not dimerize X is ______.


Which one of the following is the correct statement?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×