मराठी

Differentiate the function with respect to x. (x + 3)2 . (x + 4)3 . (x + 5)4

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प्रश्न

Differentiate the function with respect to x.

(x + 3)2 . (x + 4)3 . (x + 5)4

बेरीज
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उत्तर

Let, y = (x + 3)2 · (x + 4)3 · (x + 5)4

Taking logarithm of both sides,

log y = log [(x + 3)2 · (x + 4)3 · (x + 5)4]

= log (x + 3)2 + log (x + 4)3 + log (x + 5)4   ...[∵ log mn = log m + log n]

= 2 log (x + 3) + 3 log (x + 4) + 4 log (x + 5)  ...[∵ log mn = n log m]

Differentiating both sides with respect to x,

`1/y dy/dx = 2 d/dx log (x + 3) + 3 d/dx log (x + 4) + 4 d/dx log (x + 5)`

`1/y dy/dx = 2 * 1/(x + 3) d/dx (x + 3) + 3 xx 1/(x+ 4) d/dx (x + 4) + 4 xx 1/(x + 5) d/dx (x + 5)`

`1/y dy/dx = (2(1 + 0))/(x + 3) + (3(1 + 0))/("x" + 4) + (4(1 + 0))/(x + 5)`

`dy/dx = y [2/(x + 3) + 3/(x + 4) + 4/(x + 5)]`

`= y [(2 (x + 4) (x + 5) + 3 (x + 5) + 4 (x + 3) (x + 4))/((x + 3) (x + 4) (x + 5))]`

`= (x + 3)^2 (x + 4)^3 (x + 5)^4 xx [(2 (x^2 + 9x + 20) + 3(x^2 + 8x + 15) + 4 (x^2 + 7x + 12))/((x + 3) (x + 4) (x + 5))]`

`⇒ dy/dx= (x + 3) (x + 4)^2 (x + 5)^3 [9x^2 + 70x + 133]`

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पाठ 5: Continuity and Differentiability - Exercise 5.5 [पृष्ठ १७८]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
पाठ 5 Continuity and Differentiability
Exercise 5.5 | Q 5 | पृष्ठ १७८

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