मराठी

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प्रश्न

`8^x/x^8`

बेरीज
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उत्तर

Let y = `8^x/x^8`

Taking log on both sides, we get,

log y = `log  8^x/x^8`

⇒ log y = `log 8^x - log x^8`

⇒ log y = x log 8 – 8 log x

Differentiating both sides w.r.t. x

⇒ `1/y * "dy"/"dx" = log 8.1 - 8/x`

⇒ `"dy"/"dx" = y [log 8 - 8/x]`

Hence, `"dy"/"dx" = 8^x/x^8 [log 8 - 8/x]`

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पाठ 5: Continuity And Differentiability - Exercise [पृष्ठ १०९]

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एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 12
पाठ 5 Continuity And Differentiability
Exercise | Q 26 | पृष्ठ १०९

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