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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

Find dydx, if y = (log x)x.

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प्रश्न

Find `dy/dx`, if y = (log x)x.

बेरीज
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उत्तर

y = (log x)

Taking log of both sides,

log y = x log (logx)

Differentiating w.r.t. x,

`1/y dy/dx = x d/dx [log (log x)] + log (log x) d/dx (x)`

= `x * 1/(log x) * 1/x + log (log x) (1)`

`therefore dy/dx = y [1/(log x) + log (logx)]`

`therefore dy/dx = (log x)^x [1/(log x) + log (log x)]`

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