Advertisements
Advertisements
प्रश्न
If `y=log[x+sqrt(x^2+a^2)]` show that `(x^2+a^2)(d^2y)/(dx^2)+xdy/dx=0`
Advertisements
उत्तर
It is given that:
`y=log[x+sqrt(x^2+a^2)]`
Differentiating equation (1) with respect to x, we get
`dy/dx=(1+x/sqrt(x^2+a^2))/(x+sqrt(x^2+a^2))`
`dy/dx=1/sqrt(x^2+a^2)........(2)`
`xdy/dx=x/sqrt(x^2+a^2).........(3)`
Again differentiating equation (2) with respect to x, we get
`(d^2y)/(dx^2)=-x/(x^2+a^2)^(3/2)`
`(x^2+y^2)(d^2y)/(dx^2)=-x/sqrt(x^2+a^2)............(4)`
Adding equation (3) and (4), we get
`(x^2+y^2)(d^2y)/(dx^2)+xdy/dx=-x/sqrt(x^2+a^2)+x/sqrt(x^2+a^2)=0`
`(x^2+y^2)(d^2y)/(dx^2)+xdy/dx=0`
APPEARS IN
संबंधित प्रश्न
Differentiate the function with respect to x.
`sqrt(((x-1)(x-2))/((x-3)(x-4)(x-5)))`
Differentiate the function with respect to x.
`(x + 1/x)^x + x^((1+1/x))`
Differentiate the function with respect to x.
(log x)x + xlog x
Differentiate the function with respect to x.
`(sin x)^x + sin^(-1) sqrtx`
Differentiate the function with respect to x.
xsin x + (sin x)cos x
Differentiate (x2 – 5x + 8) (x3 + 7x + 9) in three ways mentioned below:
- By using the product rule.
- By expanding the product to obtain a single polynomial.
- By logarithmic differentiation.
Do they all give the same answer?
Differentiate the function with respect to x:
xx + xa + ax + aa, for some fixed a > 0 and x > 0
If `(sin "x")^"y" = "x" + "y", "find" (d"y")/(d"x")`
If x = a cos3t, y = a sin3t, show that `"dy"/"dx" = -(y/x)^(1/3)`.
If x = log(1 + t2), y = t – tan–1t,show that `"dy"/"dx" = sqrt(e^x - 1)/(2)`.
Find the second order derivatives of the following : log(logx)
Find the nth derivative of the following: log (ax + b)
If y = `25^(log_5sin_x) + 16^(log_4cos_x)` then `("d"y)/("d"x)` = ______.
If y = 5x. x5. xx. 55 , find `("d"y)/("d"x)`
If x7 . y5 = (x + y)12, show that `("d"y)/("d"x) = y/x`
If y = `("e"^"2x" sin x)/(x cos x), "then" "dy"/"dx" = ?`
Derivative of `log_6`x with respect 6x to is ______
`2^(cos^(2_x)`
`8^x/x^8`
`log [log(logx^5)]`
If xm . yn = (x + y)m+n, prove that `"dy"/"dx" = y/x`
If `"f" ("x") = sqrt (1 + "cos"^2 ("x"^2)), "then the value of f'" (sqrtpi/2)` is ____________.
The derivative of x2x w.r.t. x is ______.
If xy = yx, then find `dy/dx`
