मराठी

If y = e^(acos^(-1)x), −1 ≤ x ≤ 1, show that (1- x^2) (d^2y)/(dx^2) -x dy/dx - a^2y = 0.

Advertisements
Advertisements

प्रश्न

If y = `e^(acos^(-1)x)`, −1 ≤ x ≤ 1, show that `(1- x^2) (d^2y)/(dx^2) -x dy/dx - a^2y = 0`.

बेरीज
Advertisements

उत्तर

We have y = `e^(a cos^(-1)x)`  ...(1)

Differentiating (1) both sides w.r.t. x, we get

`dy/dx = e^(a cos^(-1)x) d/dx (a cos^-1 x)`

`= e^(a cos^(-1)x) ((- a)/sqrt(1 - x^2))`

`= (- ay)/(sqrt(1 - x^2))`   ...(2)

Differentiating (2) both sides w.r.t. x, we get

`(d^2y)/(dx^2) = -a[(sqrt(1-x^2) dy/dx - y d/dx sqrt(1 - x^2))/((1-x^2))]`

`(d^2y)/(dx^2) = -a[(sqrt(1-x^2)dy/dx - y/(2sqrt(1-x^2)) * (-2x))/((1-x^2))]`

`(1 - x^2) (d^2y)/dx^2 = -a[-ay + (xy)/sqrt(1-x^2)]` ....[from (2)]

`(1 - x^2) (d^2y)/dx^2 = -a[-ay + x * ((-1)/a * dy/dx)]`

`(1 - x^2) (d^2y)/(dx^2) = a^2y + x dy/dx`

`(1 - x^2) (d^2y)/(dx^2) - x dy/dx - a^2y = 0`

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 5: Continuity and Differentiability - Exercise 5.9 [पृष्ठ १९२]

APPEARS IN

एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
पाठ 5 Continuity and Differentiability
Exercise 5.9 | Q 23 | पृष्ठ १९२

व्हिडिओ ट्यूटोरियलVIEW ALL [3]

संबंधित प्रश्‍न

 

if xx+xy+yx=ab, then find `dy/dx`.


Differentiate the function with respect to x.

(log x)x + xlog x


Differentiate the function with respect to x.

`(x cos x)^x + (x sin x)^(1/x)`


Differentiate the function with respect to x:

xx + xa + ax + aa, for some fixed a > 0 and x > 0


If cos y = x cos (a + y), with cos a ≠ ± 1, prove that `dy/dx = cos^2(a+y)/(sin a)`.


If x = a (cos t + t sin t) and y = a (sin t – t cos t), find `(d^2y)/dx^2`.


if `x^m y^n = (x + y)^(m + n)`, prove that `(d^2y)/(dx^2)= 0`


Find `(dy)/(dx) , if y = sin ^(-1) [2^(x +1 )/(1+4^x)]`


Evaluate 
`int  1/(16 - 9x^2) dx`


Differentiate  
log (1 + x2) w.r.t. tan-1 (x)


Find `(d^2y)/(dx^2)` , if y = log x


Differentiate : log (1 + x2)  w.r.t. cot-1 x. 


If `"x"^(5/3) . "y"^(2/3) = ("x + y")^(7/3)` , the show that `"dy"/"dx" = "y"/"x"`


 Solve the following differential equation: (3xy + y2) dx + (x2 + xy) dy = 0 


`"If"  y = sqrt(logx + sqrt(log x + sqrt(log x + ... ∞))), "then show that"  dy/dx = (1)/(x(2y - 1).`


If y = `x^(x^(x^(.^(.^.∞))`, then show that `"dy"/"dx" = y^2/(x(1 - logy).`.


If x = esin3t, y = ecos3t, then show that `dy/dx = -(ylogx)/(xlogy)`.


If x = sin–1(et), y = `sqrt(1 - e^(2t)), "show that"  sin x + dy/dx` = 0


If x = `(2bt)/(1 + t^2), y = a((1 - t^2)/(1 + t^2)), "show that" "dx"/"dy" = -(b^2y)/(a^2x)`.


Find the second order derivatives of the following : x3.logx


Find the nth derivative of the following: log (ax + b)


Find the nth derivative of the following : log (2x + 3)


If y = log [cos(x5)] then find `("d"y)/("d"x)`


If x7 . y5 = (x + y)12, show that `("d"y)/("d"x) = y/x`


Derivative of loge2 (logx) with respect to x is _______.


If y = `("e"^"2x" sin x)/(x cos x), "then" "dy"/"dx" = ?`


`8^x/x^8`


`log (x + sqrt(x^2 + "a"))`


`lim_("x" -> 0)(1 - "cos x")/"x"^2` is equal to ____________.


If y `= "e"^(3"x" + 7), "then the value" |("dy")/("dx")|_("x" = 0)` is ____________.


Evaluate:

`int log x dx`


Find the derivative of `y = log x + 1/x` with respect to x.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×