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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

Find the second order derivatives of the following : log(logx)

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प्रश्न

Find the second order derivatives of the following : log(logx)

बेरीज
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उत्तर

Let y = log(logx)
Then `"dy"/"dx" = "d"/"dx"[log (logx)]`

= `(1)/"logx" . "d"/"dx"(logx)`

= `(1)/"logx" xx (1)/x = (1)/"xlogx"`
and
`(d^2y)/(dx^2) = "d"/"dx"(xlogx)^-1`

= `(-1)(xlogx)^-2."d"/"dx"(xlogx)`

= `(-1)/(xlogx)^2.[x"d"/"dx"(logx) + (logx)."d"/"dx"(x)]`

= `(-1)/(xlogx)^2.[x xx 1/x + (logx) xx 1]`

= `-(1 + logx)/(xlogx)^2`.

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पाठ 1: Differentiation - Exercise 1.5 [पृष्ठ ६०]

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