Advertisements
Advertisements
प्रश्न
Determine the amount of CaCl2 (i = 2.47) dissolved in 2.5 litre of water such that its osmotic pressure is 0.75 atm at 27°C.
Advertisements
उत्तर
Given: Osmotic pressure (π) = 0.75 atm
Volume (V) = 2.5 L
i = 2.47
R = 0.0821 L atm K−1 mol−1
Temperature (T) = 27°C = 27 + 273 = 300 K
π = iCRT
or, π = `i n/V RT`
or, n = `(π xx V)/(i xx R xx T)`
= `(0.75 atm xx 2.5 L)/(2.47 xx 0.0821 L atm K^-1 mol^-1 xx 300 K)`
= `1.875/60.836`
= 0.0308 mol
Molar mass of CaCl2 = 40 + 2 × 35.5
= 111 g mol−1
∴ Amount of CaCl2 dissolved = 0.0308 × 111 g
= 3.42 g
संबंधित प्रश्न
Determine the osmotic pressure of a solution prepared by dissolving 2.5 × 10−2 g of K2SO4 in 2L of water at 25°C, assuming that it is completely dissociated.
(R = 0.0821 L atm K−1 mol−1, Molar mass of K2SO4 = 174 g mol−1)
Which of the following is not a colligative property?
What happens when the external pressure applied becomes more than the osmotic pressure of solution?
Blood cells are isotonic with 0.9% sodium chloride solution. What happens if we place blood cells in a solution containing
(i) 1.2% sodium chloride solution?
(ii) 0.4% sodium chloride solution?
Define osmotic pressure.
Define Semipermeable membrane
Define the following term:
isotonic solution
Answer the following in one or two sentences.
What is osmotic pressure?
Answer the following.
The osmotic pressure of CaCl2 and urea solutions of the same concentration at the same temperature are respectively 0.605 atm and 0.245 atm, calculate van’t Hoff factor for CaCl2.
Answer the following.
How molar mass of a solute is determined by osmotic pressure measurement?
Explain the osmotic pressure of a solution with the help of a thistle tube.
At constant temperature the osmotic pressure of a solution is ____________.
A solution containing 10 g per dm3 of urea (molar mass 60 g mol−1) is isotonic with 5% solution of non-volatile solute, MB of solute is:
The temperature at which 10% aqueous solution of (W/V) of glucose will show the osmotic pressure of 16.4 atoms is: (R = 0.082 L atom K−1 mol−1)
Isotonic solutions must have the same:
(i) solute
(ii) density
(iii) elevation in boiling point
(iv) depression in freezing point
In isotonic solutions:
(i) Solute and solvent both are same.
(ii) Osmotic pressure is same.
(iii) Solute and solvent may or may not be same.
(iv) Solute is always same solvent may be different.
Isotonic solutions have same
Which one of the following is a colligative property?
Arrange the following solutions in the order of increasing osmotic pressure (π) assuming complete ionization.
- 0.5M Li2 SO4
- 0.5M KCl
- 0.5M Al2 (SO4)3
- 0.1 M BaCl2
Define reverse osmosis.
Name the four colligative properties that are oftently used for determination of molecular mass.
How will you determine molar mass of solute from osmotic pressure?
Write the condition of reverse osmosis.
Calculate the osmotic pressure of 0.03 mole of non electrolyte solute dissolved in 0.1 dm3 of water at 300 K. [R = 0.082 dm3 atm mol-1 K-1]
The 'X' g nonvolatile solute having molar mass 196 g mol-1 is dissolved in 3 dm³ water. Calculate the value of 'X' if resulting solution has osmotic pressure 0.8 atm at 300 К.
(R = 0.0821dm³ atm K-1 mol-1)
Calculate the osmotic pressure of 0.2 M aqueous solution of nonelectrolyte at 300 K.
[R = 0.082 atm dm3 mol−1K−1]
