Advertisements
Advertisements
प्रश्न
Depict the orientation of the dipole in (i) stable, (ii) unstable equilibrium in a uniform electric field.
Advertisements
उत्तर
Depicting the orientation of the dipole in
(i) stable equilibrium in a uniform electric field
Net force is zero in this case as qE - qE = 0
Net torque = pEsinθ as θ = 0°
(ii) unstable equilibrium in a uniform electric field.
Net force is negative in this case as - qE - qE = -2qE
Net torque = pEsinθ as θ = 180°
APPEARS IN
संबंधित प्रश्न
Derive the expression for the electric potential due to an electric dipole at a point on its axial line.
Write the expression for the torque \[\vec{\tau}\] acting on a dipole of dipole moment \[\vec{p}\] placed in an electric field \[\vec{E}\].
Define electric dipole moment. Is it a scalar or a vector? Derive the expression for the electric field of a dipole at a point on the equatorial plane of the dipole.
Two particles A and B, of opposite charges 2.0 × 10−6 C and −2.0 × 10−6 C, are placed at a separation of 1.0 cm.
An electric dipole is placed at an angle of 30° with an electric field intensity of 2 × 105 N/C. It experiences a torque equal to 4 Nm. The charge on the dipole, if the dipole length is 2 cm, is ______.
Dimensions of mass in electric field and in electric dipole moment are respectively.
A short electric dipole bas a dipole moment of 16 x 10-9 C m. The electric potential due to the dipole at a point at a distance of 0.6 m from the centre of the dipole, situated on a line making an angle of 60° with the dipole axis is: ____________. `(1/(4piepsilon_0) = 9 xx 10^9 "Nm"^2// "C"^2)`
The unit of electric dipole moment is ______.
The region surrounding a stationary electric dipole has ______
The electric potential V as a function of distance X is shown in the figure.
The graph of the magnitude of electric field intensity E as a function of X is ______.
