Advertisements
Advertisements
प्रश्न
Derive an expression for the intensity of electric field at a point in broadside position or on [4)
an equatorial line of an electric dipole.
Advertisements
उत्तर
The electric field at a point, P due to an electric dipole.Due to the positive charge, the positive test charge will experience repulsive force whereas due to negative charge test charge will experience the attraction. Hence,

`|E_+| = 1/(4piin_0) q/(r^2 + a^2)`
`|E_-| = 1/(4piin_0) q/(r^2 + a^2)`
`E_R = E_+cos theta + E_- cos theta`
`= 1/(4piin_o) (2q)/(r^2 + a^2) . cos theta`
`= 1/(4piin_0) (2p)/(r^2 + a^2) . (q/(r^2 + a^2)^(1/2))`
`E_R = 1/()4piin_0 (2q xx a)/(r^2 + a^2)^(3/2) = 1/(4piin_0) p/(r^2 + a^2)^(3/2)`
if r >>> a, then
`E_R = 1/(4piin_0) p/r^3`
APPEARS IN
संबंधित प्रश्न
An electric dipole of length 4 cm, when placed with its axis making an angle of 60° with a uniform electric field, experiences a torque of `4sqrt3`Nm. Calculate the potential energy of the dipole, if it has charge ±8 nC
An electric dipole of length 2 cm, when placed with its axis making an angle of 60° with a uniform electric field, experiences a torque of \[8\sqrt{3}\] Nm. Calculate the potential energy of the dipole, if it has a charge \[\pm\] 4 nC.
A sample of HCI gas is placed in an electric field of 2.5 × 104 NC−1. The dipole moment of each HCI molecule is 3.4 × 10−30 Cm. Find the maximum torque that can act on a molecule.
Two particles A and B, of opposite charges 2.0 × 10−6 C and −2.0 × 10−6 C, are placed at a separation of 1.0 cm.
Two charges + 3.2 x 10-19 C and --3.2 x 10-19 C placed at 2.4 Å apart to form an electric dipole. lt is placed in a uniform electric field of intensity 4 x 105 volt/m. The electric dipole moment is ______.
An electric dipole of moment p is placed parallel to the uniform electric field. The amount of work done in rotating the dipole by 90° is ____________.
In the derivation of the electric field at the equatorial line, why do the components perpendicular to the dipole axis cancel out?
For a short dipole, the ratio of the electric field on the axial line to that on the equatorial line (at the same distance r) is:
The electric potential at a point P due to a dipole (at distance r from the centre, at angle θ from the dipole axis) is given by:
