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प्रश्न
Derive an expression for the intensity of electric field at a point in broadside position or on [4)
an equatorial line of an electric dipole.
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उत्तर
The electric field at a point, P due to an electric dipole.Due to the positive charge, the positive test charge will experience repulsive force whereas due to negative charge test charge will experience the attraction. Hence,
`|E_+| = 1/(4piin_0) q/(r^2 + a^2)`
`|E_-| = 1/(4piin_0) q/(r^2 + a^2)`
`E_R = E_+cos theta + E_- cos theta`
`= 1/(4piin_o) (2q)/(r^2 + a^2) . cos theta`
`= 1/(4piin_0) (2p)/(r^2 + a^2) . (q/(r^2 + a^2)^(1/2))`
`E_R = 1/()4piin_0 (2q xx a)/(r^2 + a^2)^(3/2) = 1/(4piin_0) p/(r^2 + a^2)^(3/2)`
if r >>> a, then
`E_R = 1/(4piin_0) p/r^3`
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संबंधित प्रश्न
Write the expression for the torque \[\vec{\tau}\] acting on a dipole of dipole moment \[\vec{p}\] placed in an electric field \[\vec{E}\].
Find the resultant electric field due to an electric dipole of dipole moment, 2aq, (2a being the separation between the charges ±± q) at a point distant 'x' on its equator.
An electric dipole is placed at the centre of a sphere. Mark the correct options.
(a) The flux of the electric field through the sphere is zero.
(b) The electric field is zero at every point of the sphere.
(c) The electric field is not zero anywhere on the sphere.
(d) The electric field is zero on a circle on the sphere.
Dimensions of mass in electric field and in electric dipole moment are respectively.
An electric dipole is placed at an angle of 30° to a non-uniform electric field. The dipole will experience ________.
A dipole is placed in an electric field as shown. In which direction will it move?
Show that intensity of electric field at a point in broadside position of an electric dipole is given by:
E = `(1/(4 pi epsilon_0)) p/((r^2 + l^2)^(3//2))`
Where the terms have their usual meaning.
