Advertisements
Advertisements
प्रश्न
\[\int\frac{\cot x}{\sqrt{\sin x}} dx\]
Advertisements
उत्तर
\[\int\frac{\cot x}{\sqrt{\sin x}}dx\]
\[ = \int\frac{\cos x}{\sin x \sqrt{\sin x}} dx\]
\[ = \int\frac{\cos x}{\left( \sin x \right)^\frac{3}{2}}dx\]
\[Let \sin x = t\]
\[ \Rightarrow \cos x = \frac{dt}{dx}\]
\[ \Rightarrow \text{cos x dx} = dt\]
\[Now, \int\frac{\cos x}{\left( \sin x \right)^\frac{3}{2}}dx\]
\[ = \int\frac{dt}{t^\frac{3}{2}}\]
\[ = \int t^{- \frac{3}{2}} dt\]
\[ = \left[ \frac{t^{- \frac{3}{2} + 1}}{\frac{- 3}{2} + 1} \right] + C\]
\[ = \frac{- 2}{\sqrt{t}} + C\]
\[ = - \frac{2}{\sqrt{\sin x}} + C\]
APPEARS IN
संबंधित प्रश्न
Evaluate : `int_0^3dx/(9+x^2)`
Evaluate the following integrals:
\[\int\frac{\left\{ e^{\sin^{- 1} }x \right\}^2}{\sqrt{1 - x^2}} dx\]
\[\int\frac{1}{\sqrt{1 - x^2} \left( \sin^{- 1} x \right)^2} dx\]
Evaluate the following integrals:
Evaluate the following integrals:
Evaluate the following integral :-
Evaluate the following integral :-
Evaluate the following integral:
Evaluate the following integrals:
Evaluate:\[\int\frac{\sec^2 \sqrt{x}}{\sqrt{x}} \text{ dx }\]
Evaluate:\[\int\frac{\sin \sqrt{x}}{\sqrt{x}} \text{ dx }\]
Evaluate:\[\int\frac{\log x}{x} \text{ dx }\]
Evaluate: \[\int\frac{x^3 - x^2 + x - 1}{x - 1} \text{ dx }\]
Write the value of\[\int\sec x \left( \sec x + \tan x \right)\text{ dx }\]
Evaluate: \[\int\frac{1}{x^2 + 16}\text{ dx }\]
Evaluate: \[\int\left( 1 - x \right)\sqrt{x}\text{ dx }\]
Evaluate:
`∫ (1)/(sin^2 x cos^2 x) dx`
Evaluate: `int_ (x + sin x)/(1 + cos x ) dx`
Evaluate the following:
`int ("d"x)/sqrt(16 - 9x^2)`
Evaluate the following:
`int (3x - 1)/sqrt(x^2 + 9) "d"x`
Evaluate the following:
`int sqrt(x)/(sqrt("a"^3 - x^3)) "d"x`
