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प्रश्न
\[\int\frac{\cot x}{\sqrt{\sin x}} dx\]
योग
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उत्तर
\[\int\frac{\cot x}{\sqrt{\sin x}}dx\]
\[ = \int\frac{\cos x}{\sin x \sqrt{\sin x}} dx\]
\[ = \int\frac{\cos x}{\left( \sin x \right)^\frac{3}{2}}dx\]
\[Let \sin x = t\]
\[ \Rightarrow \cos x = \frac{dt}{dx}\]
\[ \Rightarrow \text{cos x dx} = dt\]
\[Now, \int\frac{\cos x}{\left( \sin x \right)^\frac{3}{2}}dx\]
\[ = \int\frac{dt}{t^\frac{3}{2}}\]
\[ = \int t^{- \frac{3}{2}} dt\]
\[ = \left[ \frac{t^{- \frac{3}{2} + 1}}{\frac{- 3}{2} + 1} \right] + C\]
\[ = \frac{- 2}{\sqrt{t}} + C\]
\[ = - \frac{2}{\sqrt{\sin x}} + C\]
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