Evaluate: ∫ 1 X 2 + 16 D X - Mathematics

प्रश्न

Evaluate: \[\int\frac{1}{x^2 + 16}\text{ dx }\]

बेरीज

उत्तर

\[\int\frac{1}{x^2 + 16}dx = \int\frac{1}{x^2 + 4^2}dx\]
\[ = \frac{1}{4} \tan^{- 1} \frac{x}{4} + c\]
\[\text{ Hence,} \int\frac{1}{x^2 + 16}dx = \frac{1}{4} \tan^{- 1} \frac{x}{4} + c\]

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Evaluation of Simple Integrals of the Following Types and Problems

या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?

Q 53 Q 52 Q 54

पाठ 19: Indefinite Integrals - Very Short Answers [पृष्ठ १९८]

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आरडी शर्मा Mathematics [English] Class 12

पाठ 19 Indefinite Integrals
Very Short Answers | Q 53 | पृष्ठ १९८

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