Advertisements
Advertisements
प्रश्न
Evaluate: \[\int\left( 1 - x \right)\sqrt{x}\text{ dx }\]
Advertisements
उत्तर
\[ = \int\left( x^\frac{1}{2} - x^\frac{3}{2} \right) dx\]
\[ = \frac{x^\frac{1}{2} + 1}{\frac{1}{2} + 1} - \frac{x^\frac{3}{2} + 1}{\frac{3}{2} + 1} + c\]
\[ = \frac{2}{3} x^\frac{3}{2} - \frac{2}{5} x^\frac{5}{2} + c\]
\[\text{ Hence,} \int\left( 1 - x \right)\sqrt{x} \text{ dx }= \frac{2}{3} x^\frac{3}{2} - \frac{2}{5} x^\frac{5}{2} + c\]
APPEARS IN
संबंधित प्रश्न
Evaluate : `int_0^3dx/(9+x^2)`
\[\int\frac{\left\{ e^{\sin^{- 1} }x \right\}^2}{\sqrt{1 - x^2}} dx\]
\[\int\frac{1}{\sqrt{1 - x^2} \left( \sin^{- 1} x \right)^2} dx\]
Evaluate the following integrals:
Evaluate the following integrals:
Evaluate the following integrals:
Evaluate the following integrals:
Evaluate the following integral :-
Evaluate the following integral:
Evaluate the following integral:
Evaluate the following integrals:
Evaluate the following integral:
Evaluate the following integral:
Write a value of
Evaluate: \[\int\frac{x^3 - x^2 + x - 1}{x - 1} \text{ dx }\]
Evaluate:
\[\int \cos^{-1} \left(\sin x \right) \text{dx}\]
Evaluate the following:
`int sqrt(1 + x^2)/x^4 "d"x`
Evaluate the following:
`int ("d"x)/sqrt(16 - 9x^2)`
Evaluate the following:
`int sqrt(5 - 2x + x^2) "d"x`
Evaluate the following:
`int x/(x^4 - 1) "d"x`
Evaluate the following:
`int sqrt(x)/(sqrt("a"^3 - x^3)) "d"x`
Evaluate the following:
`int_1^2 ("d"x)/sqrt((x - 1)(2 - x))`
