Advertisements
Advertisements
प्रश्न
Advertisements
उत्तर
\[\int\sqrt{\frac{1 - \cos x}{1 + \cos x}} dx\]
` ∫ \sqrt {{2 sin^2 x/2} / {2 cos^2 x/2 }} dx` `[ ∵ 1 - cos x = 2 sin^2 x/2 & 1 + cos x = 2 cos ^2 x/2]`
\[ = \int\tan\frac{x}{2} dx\]
\[ =\text{ - 2 }\text{ln }\left| \cos\frac{x}{2} \right| + C\]
APPEARS IN
संबंधित प्रश्न
Evaluate the following integrals:
Evaluate the following integral :-
Evaluate the following integral:
Evaluate the following integral:
Evaluate the following integrals:
Evaluate the following integral:
Evaluate the following integral:
Write a value of
Evaluate:\[\int \sec^2 \left( 7 - 4x \right) \text{ dx }\]
Evaluate: \[\int 2^x \text{ dx }\]
Evaluate: \[\int\frac{1}{\sqrt{1 - x^2}} \text{ dx }\]
Evaluate: \[\int\left( 1 - x \right)\sqrt{x}\text{ dx }\]
Evaluate: \[\int\frac{x + \cos6x}{3 x^2 + \sin6x}\text{ dx }\]
Evaluate: \[\int\frac{2}{1 - \cos2x}\text{ dx }\]
Evaluate : \[\int\frac{1}{x(1 + \log x)} \text{ dx}\]
Evaluate: `int_ (x + sin x)/(1 + cos x ) dx`
Evaluate the following:
`int (3x - 1)/sqrt(x^2 + 9) "d"x`
Evaluate the following:
`int sqrt(5 - 2x + x^2) "d"x`
Evaluate the following:
`int x/(x^4 - 1) "d"x`
Evaluate the following:
`int sqrt(2"a"x - x^2) "d"x`
Evaluate the following:
`int_1^2 ("d"x)/sqrt((x - 1)(2 - x))`
