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प्रश्न
Construct a rhombus whose diagonals are of length 10 cm and 6 cm.
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उत्तर

1. Draw AC equal to 10 cm.
2. Draw XY, the right bisector of AC, meeting it at O.
3. With O as centre and radius equal to half of the length of the other diagonal,
i.e. 3 cm, cut OB = OD = 3 cm.
4. Join AB, AD and CB, CD.
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संबंधित प्रश्न
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Diagonals of parallelogram ABCD intersect at O as shown in the following fegure. XY contains O, and X, Y are points on opposite sides of the parallelogram. Give reasons for each of the following:
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(ii) ∠OBY = ∠ODX
(iii) ∠BOY = ∠DOX
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(iii) \[\angle DCE = \frac{1}{2}\angle C\]
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(ii) Also state, if ∠BCO = ∠DCO.
