Advertisements
Advertisements
प्रश्न
Construct a rhombus whose diagonals are of length 10 cm and 6 cm.
Advertisements
उत्तर
1. Draw AC equal to 10 cm.
2. Draw XY, the right bisector of AC, meeting it at O.
3. With O as centre and radius equal to half of the length of the other diagonal,
i.e. 3 cm, cut OB = OD = 3 cm.
4. Join AB, AD and CB, CD.
APPEARS IN
संबंधित प्रश्न
In the following figure RISK and CLUE are parallelograms. Find the measure of x.
Find the angles marked with a question mark shown in Fig. 17.27
Which of the following statement is true for a rhombus?
It has only two pairs of equal sides.
The diagonals of a quadrilateral are perpendicular to each other. Is such a quadrilateral always a rhombus? If your answer is 'No', draw a figure to justify your answer.
ABCD is a rhombus. If ∠ACB = 40°, find ∠ADB.
Identify all the quadrilateral that have Four sides of equal length
State with reason whether the following statement is ‘true’ or ‘false’.
Every rhombus is a rectangle.
The given figure shows a rhombus ABCD in which angle BCD = 80°. Find angles x and y.
All rhombuses are squares.
ABCD is a rhombus such that the perpendicular bisector of AB passes through D. Find the angles of the rhombus.
Hint: Join BD. Then ∆ABD is equilateral.
