मराठी

Construct a triangle BCP given BC = 5 cm, BP = 4 cm and ∠PBC = 45°. Complete the rectangle ABCD such that: P is equidistant from AB and BC. P is equidistant from C and D. - Mathematics

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प्रश्न

Construct a triangle BCP given BC = 5 cm, BP = 4 cm and ∠PBC = 45°.

  1. Complete the rectangle ABCD such that:
    1. P is equidistant from AB and BC.
    2. P is equidistant from C and D.
  2. Measure and record the length of AB. 
बेरीज
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उत्तर

   

  1. Steps of construction:
    1. Draw a line segment BC = 5 cm
    2. B as centre and radius 4 cm draw an arc at an angle of 45 degrees from BC.
    3. Join PC.
    4. B and C as centers, draw two perpendiculars to BC.
    5. P as centre and radius PC, cut an arc on the perpendicular on C at D.
    6. D as centre, draw a line parallel to BC which intersects the perpendicular on B at A.
      ABCD is the required rectangle such that P is equidistant from AB and BC (since BD is angle bisector of angle B) as well as C and D.
  2. On measuring AB = 5.7 cm
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