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Question
Construct a triangle BCP given BC = 5 cm, BP = 4 cm and ∠PBC = 45°.
- Complete the rectangle ABCD such that:
- P is equidistant from AB and BC.
- P is equidistant from C and D.
- Measure and record the length of AB.
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Solution
- Steps of construction:
- Draw a line segment BC = 5 cm
- B as centre and radius 4 cm draw an arc at an angle of 45 degrees from BC.
- Join PC.
- B and C as centers, draw two perpendiculars to BC.
- P as centre and radius PC, cut an arc on the perpendicular on C at D.
- D as centre, draw a line parallel to BC which intersects the perpendicular on B at A.
ABCD is the required rectangle such that P is equidistant from AB and BC (since BD is angle bisector of angle B) as well as C and D.
- On measuring AB = 5.7 cm
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Construct triangle BCP, when CB = 5 cm, BP = 4 cm, ∠PBC = 45°.
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Ruler and compasses only may be used in this question. All construction lines and arcs must be clearly shown, and be of sufficient length and clarity to permit assessment.
(i) Construct a ΔABC, in which BC = 6 cm, AB = 9 cm and ∠ABC = 60°.
(ii) Construct the locus of the vertices of the triangles with BC as base, which are equal in area to ΔABC.
(iii) Mark the point Q, in your construction, which would make ΔQBC equal in area to ΔABC, and isosceles.
(iv) Measure and record the length of CQ.
