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Question
Construct a triangle BCP given BC = 5 cm, BP = 4 cm and ∠PBC = 45°.
- Complete the rectangle ABCD such that:
- P is equidistant from AB and BC.
- P is equidistant from C and D.
- Measure and record the length of AB.
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Solution
- Steps of construction:
- Draw a line segment BC = 5 cm
- B as centre and radius 4 cm draw an arc at an angle of 45 degrees from BC.
- Join PC.
- B and C as centers, draw two perpendiculars to BC.
- P as centre and radius PC, cut an arc on the perpendicular on C at D.
- D as centre, draw a line parallel to BC which intersects the perpendicular on B at A.
ABCD is the required rectangle such that P is equidistant from AB and BC (since BD is angle bisector of angle B) as well as C and D.
- On measuring AB = 5.7 cm
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Construct a triangle BPC given BC = 5 cm, BP = 4 cm and .
i) complete the rectangle ABCD such that:
a) P is equidistant from AB and BCV
b) P is equidistant from C and D.
ii) Measure and record the length of AB.
