Advertisements
Advertisements
प्रश्न
Construct a rhombus CLUE in which CL = 7.5 cm and LE = 6 cm.
Advertisements
उत्तर
We know that, all sides of a rhombus are equal and opposite sides are parallel to each other.
Steps of construction:
Step I: Draw a line segment CL = 7.5 cm.
Step II: With C as a centre, draw an arc CE = 7.5 cm.
Step III: With L as a centre, draw an another arc LU = 7.5 cm.
Step IV: Now, with centre L, draw an arc LE = 6 cm, that is cut-off previous arc CE.
Step V: With E as a centre, draw an arc UE = 7.5 cm, that is cut-off previous arc LU.
Step VI: Now join UL, CE and EU.
Hence, CLUE is a required rhombus.
APPEARS IN
संबंधित प्रश्न
All rhombuses are parallelograms.
The following figure is parallelogram. Find the degree value of the unknown x, y, z.
All the angles of a quadrilateral are equal to each other. Find the measure of each. Is the quadrilateral a parallelogram? What special type of parallelogram is it?
Find the angles marked with a question mark shown in Fig. 17.27
Diagonals of parallelogram ABCD intersect at O as shown in the following fegure. XY contains O, and X, Y are points on opposite sides of the parallelogram. Give reasons for each of the following:
(i) OB = OD
(ii) ∠OBY = ∠ODX
(iii) ∠BOY = ∠DOX
(iv) ∆BOY ≅ ∆DOX
Now, state if XY is bisected at O.
The diagonals of a quadrilateral are perpendicular to each other. Is such a quadrilateral always a rhombus? If your answer is 'No', draw a figure to justify your answer.
ABCD is a rhombus and its diagonals intersect at O.
(i) Is ∆BOC ≅ ∆DOC? State the congruence condition used?
(ii) Also state, if ∠BCO = ∠DCO.
ABCD is a rhombus. If ∠BCA = 35°. find ∠ADC.
The lengths of the diagonals of a Rhombus are 12 cm and 16 cm. Find the side of the rhombus
ABCD is a rhombus such that the perpendicular bisector of AB passes through D. Find the angles of the rhombus.
Hint: Join BD. Then ∆ABD is equilateral.
