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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Consider figure and mark the correct option.

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प्रश्न

Consider figure and mark the correct option.

पर्याय

  • Activation energy of forward reaction is E1 + E2 and product is less stable than reactant.

  • Activation energy of forward reaction is E1 + E2 and product is more stable than reactant.

  • Activation energy of both forward and backward reaction is E1 + E2 and reactant is more stable than product.

  • Activation energy of backward reaction is E1 and product is more stable than reactant.

MCQ
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उत्तर

Activation energy of forward reaction is E1 + E2 and product is less stable than reactant.

Explanation:

Ea (forward) = E1 + E2

Since energy of reactants is less than products and the product is less stable than the reactant.

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पाठ 4: Chemical Kinetics - Exercises [पृष्ठ ४७]

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एनसीईआरटी एक्झांप्लर Chemistry Exemplar [English] Class 12
पाठ 4 Chemical Kinetics
Exercises | Q I. 4. | पृष्ठ ४७

संबंधित प्रश्‍न

(b) Rate constant ‘k’ of a reaction varies with temperature ‘T’ according to the equation:

`logk=logA-E_a/2.303R(1/T)`

Where Ea is the activation energy. When a graph is plotted for `logk Vs. 1/T` a straight line with a slope of −4250 K is obtained. Calculate ‘Ea’ for the reaction.(R = 8.314 JK−1 mol−1)


The rate constant of a first order reaction increases from 2 × 10−2 to 4 × 10−2 when the temperature changes from 300 K to 310 K. Calculate the energy of activation (Ea).

(log 2 = 0.301, log 3 = 0.4771, log 4 = 0.6021)


The rate constant for the decomposition of N2O5 at various temperatures is given below:

T/°C 0 20 40 60 80
105 × k/s−1 0.0787 1.70 25.7 178 2140

Draw a graph between ln k and `1/T` and calculate the values of A and Ea. Predict the rate constant at 30º and 50ºC.


The rate constant for the decomposition of hydrocarbons is 2.418 × 10−5 s−1 at 546 K. If the energy of activation is 179.9 kJ/mol, what will be the value of pre-exponential factor?


Consider a certain reaction \[\ce{A -> Products}\] with k = 2.0 × 10−2 s−1. Calculate the concentration of A remaining after 100 s if the initial concentration of A is 1.0 mol L−1.


The rate constant of a first order reaction are 0.58 S-1 at 313 K and 0.045 S-1 at 293 K. What is the energy of activation for the reaction?


Explain the following terms :

Half life period of a reaction (t1/2)

 

 

The rate of chemical reaction becomes double for every 10° rise in temperature because of ____________.


Activation energy of a chemical reaction can be determined by ______.


Total number of vibrational degrees of freedom present in CO2 molecule is


For an endothermic reaction energy of activation is Ea and enthalpy of reaction ΔH (both of there in KJ moI–1) minimum value of Ea will be ______.


The rate constant for a reaction is 1.5 × 10–7 sec–1 at 50°C. What is the value of activation energy?


The activation energy in a chemical reaction is defined as ______.


The slope of Arrhenius Plot `("In"  "k"  "v"//"s" 1/"T")` of first-order reaction is −5 × 103 K. The value of Ea of the reaction is. Choose the correct option for your answer. [Given R = 8.314 JK−1mol−1]


Arrhenius equation can be represented graphically as follows:

The (i) intercept and (ii) slope of the graph are:


The activation energy of one of the reactions in a biochemical process is 532611 J mol–1. When the temperature falls from 310 K to 300 K, the change in rate constant observed is k300 = x × 10–3 k310. The value of x is ______.

[Given: ln 10 = 2.3, R = 8.3 J K–1 mol–1]


An exothermic reaction X → Y has an activation energy 30 kJ mol-1. If energy change ΔE during the reaction is - 20 kJ, then the activation energy for the reverse reaction in kJ is ______.


Activation energy of any chemical reactions can be calculated if one knows the value of:


The rate of a reaction quadruples when temperature changes from 27°C to 57°C calculate the energy of activation. 

(Given: R = 8. 314 J K−1 mol−1, log 4 = 0.6021)


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