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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Consider figure and mark the correct option. - Chemistry

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प्रश्न

Consider figure and mark the correct option.

पर्याय

  • Activation energy of forward reaction is E1 + E2 and product is less stable than reactant.

  • Activation energy of forward reaction is E1 + E2 and product is more stable than reactant.

  • Activation energy of both forward and backward reaction is E1 + E2 and reactant is more stable than product.

  • Activation energy of backward reaction is E1 and product is more stable than reactant.

MCQ
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उत्तर

Activation energy of forward reaction is E1 + E2 and product is less stable than reactant.

Explanation:

Ea (forward) = E1 + E2

Since energy of reactants is less than products and the product is less stable than the reactant.

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पाठ 4: Chemical Kinetics - Exercises [पृष्ठ ४७]

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एनसीईआरटी एक्झांप्लर Chemistry [English] Class 12
पाठ 4 Chemical Kinetics
Exercises | Q I. 4. | पृष्ठ ४७

संबंधित प्रश्‍न

Explain a graphical method to determine activation energy of a reaction.


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What will be the effect of temperature on rate constant?


The rate of the chemical reaction doubles for an increase of 10 K in absolute temperature from 298 K. Calculate Ea.


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T/°C 0 20 40 60 80
105 × k/s−1 0.0787 1.70 25.7 178 2140

Draw a graph between ln k and `1/T` and calculate the values of A and Ea. Predict the rate constant at 30º and 50ºC.


The decomposition of A into product has value of k as 4.5 × 103 s−1 at 10°C and energy of activation 60 kJ mol−1. At what temperature would k be 1.5 × 104 s−1?


The rate of a reaction quadruples when the temperature changes from 293 K to 313 K. Calculate the energy of activation of the reaction assuming that it does not change with temperature.


Calculate activation energy for a reaction of which rate constant becomes four times when temperature changes from 30 °C to 50 °C. (Given R = 8.314 JK−1 mol−1). 


 Predict the main product of the following reactions:


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In respect of the eqn k = \[\ce{Ae^{{-E_a}/{RT}}}\] in chemical kinetics, which one of the following statement is correct?


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The (i) intercept and (ii) slope of the graph are:


Explain how and why will the rate of reaction for a given reaction be affected when the temperature at which the reaction was taking place is decreased.


The decomposition of N2O into N2 and O2 in the presence of gaseous argon follows second-order kinetics, with k = (5.0 × 1011 L mol−1 s−1) `"e"^(-(29000  "K")/"T")`. Arrhenius parameters are ______ kJ mol−1.


Which plot of ln k vs `1/T` is consistent with the Arrhenius equation?


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