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प्रश्न
Write a condition under which a bimolecular reaction is kinetically first order. Give an example of such a reaction. (Given : log2 = 0.3010,log 3 = 0.4771, log5 = 0.6990).
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उत्तर
\[\ce{ C_12 H22O11 + H2O ->[H+] C6 + \underset{Glucose}{C6H12O6} + \underset{Fructose}{C6H12O6} }\] Rate=K[C12H22O4]
Biomolecular reaction is Kinetically first order. Consider a chemical reaction between two substances when one reactanct is present in large excess.
`CH_3 COOC_2H5 +H_2O -> CH_3OOH + C_2H_5OH`
t=0 0.01mol 10mol 0 0
t 0mol 9.9mol 0.01 0.01 mol
Rate = K[CH3COOC2H5]
`Rate = K[CH_3COOC_2H_5] where K=K' [H2O]` the reaction behaves as first order reactions.
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संबंधित प्रश्न
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(i) Catalyst provides an alternative pathway to reaction mechanism.
(ii) Catalyst raises the activation energy.
(iii) Catalyst lowers the activation energy.
(iv) Catalyst alters enthalpy change of the reaction.
Oxygen is available in plenty in air yet fuels do not burn by themselves at room temperature. Explain.
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[Given: ln 10 = 2.3, R = 8.3 J K–1 mol–1]
Assertion (A): A reaction can have zero activation energy.
Reason (R): The minimum extra amount of energy absorbed by reactant molecules so that their energy becomes equal to the threshold value is called activation energy.
In the light of the above statements, choose the correct answer from the options given below:
