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प्रश्न
Write a condition under which a bimolecular reaction is kinetically first order. Give an example of such a reaction. (Given : log2 = 0.3010,log 3 = 0.4771, log5 = 0.6990).
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उत्तर
\[\ce{ C_12 H22O11 + H2O ->[H+] C6 + \underset{Glucose}{C6H12O6} + \underset{Fructose}{C6H12O6} }\] Rate=K[C12H22O4]
Biomolecular reaction is Kinetically first order. Consider a chemical reaction between two substances when one reactanct is present in large excess.
`CH_3 COOC_2H5 +H_2O -> CH_3OOH + C_2H_5OH`
t=0 0.01mol 10mol 0 0
t 0mol 9.9mol 0.01 0.01 mol
Rate = K[CH3COOC2H5]
`Rate = K[CH_3COOC_2H_5] where K=K' [H2O]` the reaction behaves as first order reactions.
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संबंधित प्रश्न
(b) Rate constant ‘k’ of a reaction varies with temperature ‘T’ according to the equation:
`logk=logA-E_a/2.303R(1/T)`
Where Ea is the activation energy. When a graph is plotted for `logk Vs. 1/T` a straight line with a slope of −4250 K is obtained. Calculate ‘Ea’ for the reaction.(R = 8.314 JK−1 mol−1)
The rate constant of a first order reaction increases from 2 × 10−2 to 4 × 10−2 when the temperature changes from 300 K to 310 K. Calculate the energy of activation (Ea).
(log 2 = 0.301, log 3 = 0.4771, log 4 = 0.6021)
The rate of the chemical reaction doubles for an increase of 10 K in absolute temperature from 298 K. Calculate Ea.
The decomposition of a hydrocarbon has value of rate constant as 2.5×104s-1 At 27° what temperature would rate constant be 7.5×104 × 3 s-1if energy of activation is 19.147 × 103 J mol-1 ?
Predict the main product of the following reactions:
The chemical reaction in which reactants require high amount of activation energy are generally ____________.
The rate of chemical reaction becomes double for every 10° rise in temperature because of ____________.
Why does the rate of a reaction increase with rise in temperature?
The activation energy in a chemical reaction is defined as ______.
Arrhenius equation can be represented graphically as follows:
The (i) intercept and (ii) slope of the graph are:
