Advertisements
Advertisements
प्रश्न
A ball is thrown up with a speed of 4.9 ms-1.
Prove that the time of ascent is equal to the time of descent.
Advertisements
उत्तर
For highest point initial velocity is zero
Acceleration due to gravity is = 9.8 ms-2.
Final velocity at ground is v
V2 - 0 = 2 X9.8 X 1.125
V = 4.9 ms-1.
Time taken to reach ground from highest point
V = u + at
4.9 = 0 + 9.8 t
T = 4.9/9.8 = 0.5 sec.
So time of ascent is equal to time descent.
APPEARS IN
संबंधित प्रश्न
Can we apply Newton’s third law to the gravitational force ? Explain your answer.
A uniform metal sphere of radius a and mass M is surrounded by a thin uniform spherical shell of equal mass and radius 4a (In the following figure). The centre of the shell falls on the surface of the inner sphere. Find the gravitational field at the points P1 and P2 shown in the figure.
How will the force of gravitation between two objects change if the distance between them is:
Infinite
What does a force do in the following case?
You twist a piece of rubber.
You can change the direction in which an object is moving by___________.
Is there a gravitational attraction between you and the book? Explain.
The value of universal gravitational constant (G) in the SI unit is ______.
State Newton’s universal law of gravitation. Express it with the mathematical form of force of gravitation?
State the universal law of gravitation and derive its mathematical expression.
For the weight of body of mass 5 kg to be zero on equator of the earth, angular velocity of the earth must be (The radius of earth = 6400 km, acceleration due to gravity = 10 m/s2).
