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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

A(– 2, 3, 4), B(1, 1, 2) and C(4, –1, 0) are three points. Find the Cartesian equations of the line AB and show that points A, B, C are collinear. - Mathematics and Statistics

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प्रश्न

A(– 2, 3, 4), B(1, 1, 2) and C(4, –1, 0) are three points. Find the Cartesian equations of the line AB and show that points A, B, C are collinear.

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उत्तर

We find the cartesian equations of the line AB.

The cartesian equations of the line passing through the points (x1, y1, z1) and  (x2, y2, z2) are

`(x - x_1)/(x_2 - x_1) = (y - y_1)/(y_2 - y_1) = (z - z_1)/(z_2 - z_1)`

Here, (x1, y1, z1) ≡ (−2, 3, 4) and (x2, y2, z2) ≡ (1, 1, 2)

∴  The required cartesian equations of the line AB are

`(x - (-2))/(1 - (-2)) = (y - 3)/(1 - 3) = (z - 4)/(2 - 4)`

∴ `(x + 2)/(1 + 2) = (y - 3)/(-2) = (z - 4)/(-2)`

∴ `(x + 2)/(3) = (y - 3)/(-2) = (z - 4)/(-2)`

C = (4, −1, 0)

For x = 4, `(x + 2)/(3) = (4 + 2)/(3)` = 2

For y = –1, `(y - 3)/(-2) = (-1 - 3)/(-2)` = 2

For z = 0, `(z - 4)/(-2) = (0 - 4)/(-2)` = 2

∴ The coordinates of C satisfy the equations of line AB.

∴ C lies on the line passing through A and B.

Hence, A, B, C are collinear.

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Vector and Cartesian Equations of a Line
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 6: Line and Plane - Exercise 6.1 [पृष्ठ २००]

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