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∫ 1 √ a 2 − B 2 X 2 D X - Mathematics

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प्रश्न

\[\int\frac{1}{\sqrt{a^2 - b^2 x^2}} dx\]
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उत्तर

\[\int\frac{dx}{\sqrt{a^2 - b^2 x^2}}\]
\[ = \int\frac{dx}{\sqrt{b^2 \left( \frac{a^2}{b^2} - x^2 \right)}}\]
\[ = \frac{1}{b}\int\frac{dx}{\sqrt{\left( \frac{a}{b} \right)^2 - x^2}}\]
\[ = \frac{1}{b} \sin^{- 1} \left( \frac{xb}{a} \right) + C\]

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पाठ 19: Indefinite Integrals - Exercise 19.14 [पृष्ठ ८३]

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आरडी शर्मा Mathematics [English] Class 12
पाठ 19 Indefinite Integrals
Exercise 19.14 | Q 7 | पृष्ठ ८३

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