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Solve for x: `("log"289)/("log"17)` = logx
Concept: undefined >> undefined
Express log103 + 1 in terms of log10x.
Concept: undefined >> undefined
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State, true of false:
logba =-logab
Concept: undefined >> undefined
State, true of false:
If `("log"49)/("log"7)` = log y, then y = 100.
Concept: undefined >> undefined
If log x = a and log y = b, write down
10a-1 in terms of x
Concept: undefined >> undefined
If log x = a and log y = b, write down
102b in terms of y
Concept: undefined >> undefined
If log 3 m = x and log 3 n = y, write down
32x-3 in terms of m
Concept: undefined >> undefined
If log 3 m = x and log 3 n = y, write down
`3^(1-2y+3x)` in terms of m an n
Concept: undefined >> undefined
Find x and y, if `("log"x)/("log"5) = ("log"36)/("log"6) = ("log"64)/("log"y)`
Concept: undefined >> undefined
If `"log" x^2 - "log"sqrt(y)` = 1, express y in terms of x. Hence find y when x = 2.
Concept: undefined >> undefined
If 2 log x + 1 = log 360, find: x
Concept: undefined >> undefined
If 2 log x + 1 = log 360, find: log(2 x -2)
Concept: undefined >> undefined
If 2 log x + 1 = log 360, find: log (3 x2 - 8)
Concept: undefined >> undefined
If x + log 4 + 2 log 5 + 3 log 3 + 2 log 2 = log 108, find the value of x.
Concept: undefined >> undefined
If a = `"log" 3/5, "b" = "log" 5/4 and "c" = 2 "log" sqrt(3/4`, prove that 5a+b-c = 1
Concept: undefined >> undefined
Express the following in a form free from logarithm:
3 log x - 2 log y = 2
Concept: undefined >> undefined
Express the following in a form free from logarithm:
2 log x + 3 log y = log a
Concept: undefined >> undefined
Express the following in a form free from logarithm:
m log x - n log y = 2 log 5
Concept: undefined >> undefined
Express the following in a form free from logarithm:
`2"log" x + 1/2"log" y` = 1
Concept: undefined >> undefined
Express the following in a form free from logarithm:
5 log m - 1 = 3 log n
Concept: undefined >> undefined
