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(English Medium) ICSE Class 9 - CISCE Question Bank Solutions

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Prove that the figure obtained by joining the mid-points of the adjacent sides of a rectangle is a rhombus.

[12] Mid-point and Its Converse [ Including Intercept Theorem]
Chapter: [12] Mid-point and Its Converse [ Including Intercept Theorem]
Concept: undefined >> undefined

D, E and F are the mid-points of the sides AB, BC and CA of an isosceles ΔABC in which AB = BC. Prove that ΔDEF is also isosceles.

[12] Mid-point and Its Converse [ Including Intercept Theorem]
Chapter: [12] Mid-point and Its Converse [ Including Intercept Theorem]
Concept: undefined >> undefined

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Prove that the straight lines joining the mid-points of the opposite sides of a quadrilateral bisect each other.

[12] Mid-point and Its Converse [ Including Intercept Theorem]
Chapter: [12] Mid-point and Its Converse [ Including Intercept Theorem]
Concept: undefined >> undefined

The diagonals of a quadrilateral intersect each other at right angle. Prove that the figure obtained by joining the mid-points of the adjacent sides of the quadrilateral is a rectangle.

[12] Mid-point and Its Converse [ Including Intercept Theorem]
Chapter: [12] Mid-point and Its Converse [ Including Intercept Theorem]
Concept: undefined >> undefined

If L and M are the mid-points of AB, and DC respectively of parallelogram ABCD. Prove that segment DL and BM trisect diagonal AC.

[12] Mid-point and Its Converse [ Including Intercept Theorem]
Chapter: [12] Mid-point and Its Converse [ Including Intercept Theorem]
Concept: undefined >> undefined

In a right-angled triangle ABC. ∠ABC = 90° and D is the midpoint of AC. Prove that BD = `(1)/(2)"AC"`.

[12] Mid-point and Its Converse [ Including Intercept Theorem]
Chapter: [12] Mid-point and Its Converse [ Including Intercept Theorem]
Concept: undefined >> undefined

In parallelogram ABCD, P is the mid-point of DC. Q is a point on AC such that CQ = `(1)/(4)"AC"`. PQ produced meets BC at R. Prove that

(i) R is the mid-point of BC, and

(ii) PR = `(1)/(2)"DB"`.

[12] Mid-point and Its Converse [ Including Intercept Theorem]
Chapter: [12] Mid-point and Its Converse [ Including Intercept Theorem]
Concept: undefined >> undefined

In a parallelogram ABCD, M is the mid-point AC. X and Y are the points on AB and DC respectively such that AX = CY. Prove that:
(i) Triangle AXM is congruent to triangle CYM, and

(ii) XMY is a straight line.

[12] Mid-point and Its Converse [ Including Intercept Theorem]
Chapter: [12] Mid-point and Its Converse [ Including Intercept Theorem]
Concept: undefined >> undefined

Show that the quadrilateral formed by joining the mid-points of the adjacent sides of a square is also a square.

[12] Mid-point and Its Converse [ Including Intercept Theorem]
Chapter: [12] Mid-point and Its Converse [ Including Intercept Theorem]
Concept: undefined >> undefined

In the given figure, ABCD is a trapezium. P and Q are the midpoints of non-parallel side AD and BC respectively. Find: PQ, if AB = 12 cm and DC = 10 cm.

[12] Mid-point and Its Converse [ Including Intercept Theorem]
Chapter: [12] Mid-point and Its Converse [ Including Intercept Theorem]
Concept: undefined >> undefined

In the given figure, ABCD is a trapezium. P and Q are the midpoints of non-parallel side AD and BC respectively. Find: AB, if DC = 8 cm and PQ = 9.5 cm

[12] Mid-point and Its Converse [ Including Intercept Theorem]
Chapter: [12] Mid-point and Its Converse [ Including Intercept Theorem]
Concept: undefined >> undefined

In the given figure, ABCD is a trapezium. P and Q are the midpoints of non-parallel side AD and BC respectively. Find: DC, if AB = 20 cm and PQ = 14 cm

[12] Mid-point and Its Converse [ Including Intercept Theorem]
Chapter: [12] Mid-point and Its Converse [ Including Intercept Theorem]
Concept: undefined >> undefined

In ΔABC, P is the mid-point of BC. A line through P and parallel to CA meets AB at point Q, and a line through Q and parallel to BC meets median AP at point R. Prove that: AP = 2AR

[12] Mid-point and Its Converse [ Including Intercept Theorem]
Chapter: [12] Mid-point and Its Converse [ Including Intercept Theorem]
Concept: undefined >> undefined

In ΔABC, P is the mid-point of BC. A line through P and parallel to CA meets AB at point Q, and a line through Q and parallel to BC meets median AP at point R. Prove that: BC = 4QR

[12] Mid-point and Its Converse [ Including Intercept Theorem]
Chapter: [12] Mid-point and Its Converse [ Including Intercept Theorem]
Concept: undefined >> undefined

Side AC of a ABC is produced to point E so that CE = `(1)/(2)"AC"`. D is the mid-point of BC and ED produced meets AB at F. Lines through D and C are drawn parallel to AB which meets AC at point P and EF at point R respectively. Prove that: 3DF = EF

[12] Mid-point and Its Converse [ Including Intercept Theorem]
Chapter: [12] Mid-point and Its Converse [ Including Intercept Theorem]
Concept: undefined >> undefined

Side AC of a ABC is produced to point E so that CE = `(1)/(2)"AC"`. D is the mid-point of BC and ED produced meets AB at F. Lines through D and C are drawn parallel to AB which meets AC at point P and EF at point R respectively. Prove that: 4CR = AB.

[12] Mid-point and Its Converse [ Including Intercept Theorem]
Chapter: [12] Mid-point and Its Converse [ Including Intercept Theorem]
Concept: undefined >> undefined

AD is a median of side BC of ABC. E is the midpoint of AD. BE is joined and produced to meet AC at F. Prove that AF: AC = 1 : 3.

[12] Mid-point and Its Converse [ Including Intercept Theorem]
Chapter: [12] Mid-point and Its Converse [ Including Intercept Theorem]
Concept: undefined >> undefined

ΔABC is an isosceles triangle with AB = AC. D, E and F are the mid-points of BC, AB and AC respectively. Prove that the line segment AD is perpendicular to EF and is bisected by it.

[12] Mid-point and Its Converse [ Including Intercept Theorem]
Chapter: [12] Mid-point and Its Converse [ Including Intercept Theorem]
Concept: undefined >> undefined

ABCD is a parallelogram.E is the mid-point of CD and P is a point on AC such that PC = `(1)/(4)"AC"`. EP produced meets BC at F. Prove that: F is the mid-point of BC.

[12] Mid-point and Its Converse [ Including Intercept Theorem]
Chapter: [12] Mid-point and Its Converse [ Including Intercept Theorem]
Concept: undefined >> undefined

ABCD is a parallelogram.E is the mid-point of CD and P is a point on AC such that PC = `(1)/(4)"AC"`. EP produced meets BC at F. Prove that: 2EF = BD.

[12] Mid-point and Its Converse [ Including Intercept Theorem]
Chapter: [12] Mid-point and Its Converse [ Including Intercept Theorem]
Concept: undefined >> undefined
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