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Prove that the Figure Obtained by Joining the Mid-points of the Adjacent Sides of a Rectangle is a Rhombus. - Mathematics

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प्रश्न

Prove that the figure obtained by joining the mid-points of the adjacent sides of a rectangle is a rhombus.

योग
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उत्तर


Join AC and BC.
In ΔABC, P and Q are the mid-point of AB and BC respectively.

PQ = `(1)/(2)"AC"`.......(i) and PQ || AC

In ΔBDC, R and Q are the mid-points of CD and BC respectively.

QR = `(1)/(2)"BD"`.......(ii) and QR || BD

But AC = BD  ...(diagonals of a rectangle)
From (i) and (ii)
PQ = QR
Similarly, QR = RS, RS = SP and RS || AC, SP || BD
Hence, PQ = QR = PS = SP
Therefore, PQRS is a rhombus.

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अध्याय 15: Mid-point and Intercept Theorems - Exercise 15.1

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फ्रैंक Mathematics [English] Class 9 ICSE
अध्याय 15 Mid-point and Intercept Theorems
Exercise 15.1 | Q 6

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