हिंदी

In the Given Figure, Abcd is a Trapezium. P and Q Are the Midpoints of Non-parallel Side Ad and Bc Respectively. Find: Dc, If Ab = 20 Cm and Pq = 14 Cm

Advertisements
Advertisements

प्रश्न

In the given figure, ABCD is a trapezium. P and Q are the midpoints of non-parallel side AD and BC respectively. Find: DC, if AB = 20 cm and PQ = 14 cm

योग
Advertisements

उत्तर

Let us draw a diagonal AC which meets PQ at O as shown below:

Given AB = 20 cm and PQ = 14 cm
In ΔABC,

OQ = `(1)/(2)"AB"`     ....(Mid-point Theorem)

⇒ OP = `(1)/(2) xx 20` = 10 cm

Now, 
OP = PQ - OQ
⇒ OP = 14 - 10
= 4 cm

In ΔADC,

OP = `(1)/(2)"DC"`    ....(Mid-point Theorem)

⇒ DC = 2 x OP
= 2 x 4 
= 8 cm.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 11: Midpoint and Intercept Theorems - Exercise 15.1

APPEARS IN

फ्रैंक Mathematics Part 1 [English] Class 9 ICSE
अध्याय 11 Midpoint and Intercept Theorems
Exercise 15.1 | Q 15.3

संबंधित प्रश्न

ABCD is a rectangle and P, Q, R and S are mid-points of the sides AB, BC, CD and DA respectively. Show that the quadrilateral PQRS is a rhombus.


ABCD is a trapezium in which AB || DC, BD is a diagonal and E is the mid-point of AD. A line is drawn through E parallel to AB intersecting BC at F (see the given figure). Show that F is the mid-point of BC.


ABCD is a kite having AB = AD and BC = CD. Prove that the figure formed by joining the
mid-points of the sides, in order, is a rectangle.


ABCD is a parallelogram, E and F are the mid-points of AB and CD respectively. GH is any line intersecting AD, EF and BC at G, P and H respectively. Prove that GP = PH.


Use the following figure to find:
(i) BC, if AB = 7.2 cm.
(ii) GE, if FE = 4 cm.
(iii) AE, if BD = 4.1 cm
(iv) DF, if CG = 11 cm.


D, E and F are the mid-points of the sides AB, BC and CA of an isosceles ΔABC in which AB = BC. Prove that ΔDEF is also isosceles.


If L and M are the mid-points of AB, and DC respectively of parallelogram ABCD. Prove that segment DL and BM trisect diagonal AC.


In parallelogram ABCD, P is the mid-point of DC. Q is a point on AC such that CQ = `(1)/(4)"AC"`. PQ produced meets BC at R. Prove that

(i) R is the mid-point of BC, and

(ii) PR = `(1)/(2)"DB"`.


AD is a median of side BC of ABC. E is the midpoint of AD. BE is joined and produced to meet AC at F. Prove that AF: AC = 1 : 3.


In ΔABC, the medians BE and CD are produced to the points P and Q respectively such that BE = EP and CD = DQ. Prove that: A is the mid-point of PQ.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×