हिंदी

In the Given Figure, Abcd is a Trapezium. P and Q Are the Midpoints of Non-parallel Side Ad and Bc Respectively. Find: Dc, If Ab = 20 Cm and Pq = 14 Cm

Advertisements
Advertisements

प्रश्न

In the given figure, ABCD is a trapezium. P and Q are the midpoints of non-parallel side AD and BC respectively. Find: DC, if AB = 20 cm and PQ = 14 cm

योग
Advertisements

उत्तर

Let us draw a diagonal AC which meets PQ at O as shown below:

Given AB = 20 cm and PQ = 14 cm
In ΔABC,

OQ = `(1)/(2)"AB"`     ....(Mid-point Theorem)

⇒ OP = `(1)/(2) xx 20` = 10 cm

Now, 
OP = PQ - OQ
⇒ OP = 14 - 10
= 4 cm

In ΔADC,

OP = `(1)/(2)"DC"`    ....(Mid-point Theorem)

⇒ DC = 2 x OP
= 2 x 4 
= 8 cm.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 15: Mid-point and Intercept Theorems - Exercise 15.1

APPEARS IN

फ्रैंक Mathematics [English] Class 9 ICSE
अध्याय 15 Mid-point and Intercept Theorems
Exercise 15.1 | Q 15.3

संबंधित प्रश्न

Show that the line segments joining the mid-points of the opposite sides of a quadrilateral bisect each other.


In below fig. ABCD is a parallelogram and E is the mid-point of side B If DE and AB when produced meet at F, prove that AF = 2AB.


ABC is a triang D is a point on AB such that AD = `1/4` AB and E is a point on AC such that AE = `1/4` AC. Prove that DE = `1/4` BC.


Show that the line segments joining the mid-points of the opposite sides of a quadrilateral
bisect each other.


The following figure shows a trapezium ABCD in which AB // DC. P is the mid-point of AD and PR // AB. Prove that:

PR = `[1]/[2]` ( AB + CD)


The figure, given below, shows a trapezium ABCD. M and N are the mid-point of the non-parallel sides AD and BC respectively. Find: 

  1. MN, if AB = 11 cm and DC = 8 cm.
  2. AB, if DC = 20 cm and MN = 27 cm.
  3. DC, if MN = 15 cm and AB = 23 cm.

A parallelogram ABCD has P the mid-point of Dc and Q a point of Ac such that

CQ = `[1]/[4]`AC. PQ produced meets BC at R.

Prove that
(i)R is the midpoint of BC
(ii) PR = `[1]/[2]` DB


ABCD is a parallelogram.E is the mid-point of CD and P is a point on AC such that PC = `(1)/(4)"AC"`. EP produced meets BC at F. Prove that: F is the mid-point of BC.


In a parallelogram ABCD, E and F are the midpoints of the sides AB and CD respectively. The line segments AF and BF meet the line segments DE and CE at points G and H respectively Prove that: ΔHEB ≅ ΔHFC


In ΔABC, D and E are the midpoints of the sides AB and BC respectively. F is any point on the side AC. Also, EF is parallel to AB. Prove that BFED is a parallelogram.

Remark: Figure is incorrect in Question


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×