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In a Triangle ∠Abc, ∠A = 50°, ∠B = 60° and ∠C = 70°. Find the Measures of the Angles of the Triangle Formed by Joining the Mid-points of the Sides of this Triangle. - Mathematics

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प्रश्न

In a triangle ∠ABC, ∠A = 50°, ∠B = 60° and ∠C = 70°. Find the measures of the angles of

the triangle formed by joining the mid-points of the sides of this triangle. 

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उत्तर

In ΔABC

D and E are midpoints of AB and BC

By midpoint theorem

∴ DE || AC, DE = `1/2` AC.

F is the midpoint of AC

Then, DE = `1/2` AC = CF

In a quadrilateral DECF

DE || AC, DE = CF

Hence DECF is a parallelogram

∴`∠`C = `∠`D = 70°                        [Opposite sides of parallelogram]

Similarly

BEFD is a parallelogram, `∠`B = `∠`F = 60°

ADEF is a parallelogram, `∠`A = `∠`E = 50°

∴Angles of ΔDEF

`∠`D = 70°, `∠`E = 50°, `∠`F = 60°

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अध्याय 13: Quadrilaterals - Exercise 13.4 [पृष्ठ ६२]

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आरडी शर्मा Mathematics [English] Class 9
अध्याय 13 Quadrilaterals
Exercise 13.4 | Q 2 | पृष्ठ ६२

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