हिंदी

In the Figure, □ABCD is a trapezium. AB || DC. Points P and Q are midpoints of seg AD and seg BC respectively. Then prove that, PQ || AB and PQ = ABDC12(AB+DC).

Advertisements
Advertisements

प्रश्न

In the Figure, `square`ABCD is a trapezium. AB || DC. Points P and Q are midpoints of seg AD and seg BC respectively. Then prove that, PQ || AB and PQ = `1/2 ("AB" + "DC")`.

योग
Advertisements

उत्तर

Given: `square`ABCD is a trapezium.

To prove: PQ || AB and PQ = `1/2`(AB + DC)

Construction: Extend line AQ in such a way that, on extending side DC, intersect it at point R.

Proof:

seg AB || seg DC      ...(Given)

and seg BC is their transversal.

∴ ∠ABC ≅ ∠RCB       ...(Alternate angles)

∴ ∠ABQ ≅ ∠RCQ       ...(i)   ...(B-Q-C)

In ∆ABQ and ∆RCQ,

∠ABQ ≅∠RCQ       ...[From (i)]

seg BQ ≅ seg CQ      ...(Q is the midpoint of seg BC)

∠BQA ≅ ∠CQR        ...(Vertically opposite angles)

∴ ∆ABQ ≅ ∆RCQ        ...(ASA test)

seg AB ≅ seg CR       ...(c.s.c.t.)  ...(ii)

seg AQ ≅ seg RQ      ...(c.s.c.t.)  ...(iii)

In ∆ADR,

Point P is the midpoint of line AD.       ...(Given)

Point Q is the midpoint of line AR.      ...[From (iii)]

∴ seg PQ || side DR        ...(Midpoint Theorem)

∴ seg PQ || side DC       ...(iv)    ...(D-C-R)

∴ side AB || side DC       ...(v)    ...(Given)

∴ seg PQ || side AB      ...[From (iv) and (v)]

PQ = `1/2` DR       ...(Midpoint Theorem)

= `1/2` (DC + CR)

= `1/2` (DC + AB)        ...[From (ii)]

∴ PQ = `1/2` (AB + DC)

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 5: Quadrilaterals - Problem Set 5 [पृष्ठ ७४]

APPEARS IN

बालभारती Mathematics 2 [English] Standard 9 Maharashtra State Board
अध्याय 5 Quadrilaterals
Problem Set 5 | Q 8 | पृष्ठ ७४

संबंधित प्रश्न

ABCD is a quadrilateral in which P, Q, R and S are mid-points of the sides AB, BC, CD and DA (see the given figure). AC is a diagonal. Show that:

  1. SR || AC and SR = `1/2AC`
  2. PQ = SR
  3. PQRS is a parallelogram.


ABCD is a square E, F, G and H are points on AB, BC, CD and DA respectively, such that AE = BF = CG = DH. Prove that EFGH is a square.


In a triangle, P, Q and R are the mid-points of sides BC, CA and AB respectively. If AC =
21 cm, BC = 29 cm and AB = 30 cm, find the perimeter of the quadrilateral ARPQ.


Let Abc Be an Isosceles Triangle in Which Ab = Ac. If D, E, F Be the Mid-points of the Sides Bc, Ca and a B Respectively, Show that the Segment Ad and Ef Bisect Each Other at Right Angles.


ABCD is a parallelogram, E and F are the mid-points of AB and CD respectively. GH is any line intersecting AD, EF and BC at G, P and H respectively. Prove that GP = PH.


Show that the line segments joining the mid-points of the opposite sides of a quadrilateral
bisect each other.


In triangle ABC, M is mid-point of AB and a straight line through M and parallel to BC cuts AC in N. Find the lengths of AN and MN if Bc = 7 cm and Ac = 5 cm.


D, E, and F are the mid-points of the sides AB, BC and CA of an isosceles ΔABC in which AB = BC.

Prove that ΔDEF is also isosceles.


The figure, given below, shows a trapezium ABCD. M and N are the mid-point of the non-parallel sides AD and BC respectively. Find: 

  1. MN, if AB = 11 cm and DC = 8 cm.
  2. AB, if DC = 20 cm and MN = 27 cm.
  3. DC, if MN = 15 cm and AB = 23 cm.

In triangle ABC, AD is the median and DE, drawn parallel to side BA, meets AC at point E.
Show that BE is also a median.


The side AC of a triangle ABC is produced to point E so that CE = AC. D is the mid-point of BC and ED produced meets AB at F. Lines through D and C are drawn parallel to AB which meet AC at point P and EF at point R respectively.

Prove that:

  1. 3DF = EF
  2. 4CR = AB

In ΔABC, D is the mid-point of AB and E is the mid-point of BC.

Calculate:
(i) DE, if AC = 8.6 cm
(ii) ∠DEB, if ∠ACB = 72°


In ΔABC, D, E, F are the midpoints of BC, CA and AB respectively. Find ∠FDB if ∠ACB = 115°.


In a right-angled triangle ABC. ∠ABC = 90° and D is the midpoint of AC. Prove that BD = `(1)/(2)"AC"`.


Side AC of a ABC is produced to point E so that CE = `(1)/(2)"AC"`. D is the mid-point of BC and ED produced meets AB at F. Lines through D and C are drawn parallel to AB which meets AC at point P and EF at point R respectively. Prove that: 3DF = EF


In ΔABC, X is the mid-point of AB, and Y is the mid-point of AC. BY and CX are produced and meet the straight line through A parallel to BC at P and Q respectively. Prove AP = AQ.


In ΔABC, the medians BE and CD are produced to the points P and Q respectively such that BE = EP and CD = DQ. Prove that: Q A and P are collinear.


The figure obtained by joining the mid-points of the sides of a rhombus, taken in order, is ______.


D, E and F are the mid-points of the sides BC, CA and AB, respectively of an equilateral triangle ABC. Show that ∆DEF is also an equilateral triangle.


D, E and F are respectively the mid-points of the sides AB, BC and CA of a triangle ABC. Prove that by joining these mid-points D, E and F, the triangles ABC is divided into four congruent triangles.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×