हिंदी

ΔAbc is an Isosceles Triangle with Ab = Ac. D, E and F Are the Mid-points of Bc, Ab and Ac Respectively. Prove that the Line Segment Ad is Perpendicular to Ef and is Bisected by It.

Advertisements
Advertisements

प्रश्न

ΔABC is an isosceles triangle with AB = AC. D, E and F are the mid-points of BC, AB and AC respectively. Prove that the line segment AD is perpendicular to EF and is bisected by it.

योग
Advertisements

उत्तर


Since the segment joining the mid-points of two sides of a triangle is parallel to third side and is half of it,
Therefore,
DE || AB, DE = `(1)/(2)"AB"`

Also,

DF || AC, DF = `(1)/(2)"AC"`

But AB = AC

⇒ `(1)/(2)"AB" = (1)/(2)"AC"`

⇒ DF = DE    ........(i)

DE = `(1)/(2)"AB"`

⇒ DE = AF   ........(ii)

And DF = `(1)/(2)"AC"`

⇒ DF = AE  ........(iii)

From (i), (ii) and (iii)
DE = AE = EF = DF
⇒ DEAF is a rhombus.
⇒ Diagonals AD and EF bisect each other at right angles.
⇒ AD perpendicular to EF and AD is bisected by EF.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 15: Mid-point and Intercept Theorems - Exercise 15.1

APPEARS IN

फ्रैंक Mathematics [English] Class 9 ICSE
अध्याय 15 Mid-point and Intercept Theorems
Exercise 15.1 | Q 20

संबंधित प्रश्न

In below fig. ABCD is a parallelogram and E is the mid-point of side B If DE and AB when produced meet at F, prove that AF = 2AB.


In ∆ABC, E is the mid-point of the median AD, and BE produced meets side AC at point Q.

Show that BE: EQ = 3: 1.


In the figure, give below, 2AD = AB, P is mid-point of AB, Q is mid-point of DR and PR // BS. Prove that:
(i) AQ // BS
(ii) DS = 3 Rs.


In triangle ABC ; D and E are mid-points of the sides AB and AC respectively. Through E, a straight line is drawn parallel to AB to meet BC at F.
Prove that BDEF is a parallelogram. If AB = 16 cm, AC = 12 cm and BC = 18 cm,
find the perimeter of the parallelogram BDEF.


In ΔABC, AB = 12 cm and AC = 9 cm. If M is the mid-point of AB and a straight line through M parallel to AC cuts BC in N, what is the length of MN?


Prove that the figure obtained by joining the mid-points of the adjacent sides of a rectangle is a rhombus.


In parallelogram ABCD, P is the mid-point of DC. Q is a point on AC such that CQ = `(1)/(4)"AC"`. PQ produced meets BC at R. Prove that

(i) R is the mid-point of BC, and

(ii) PR = `(1)/(2)"DB"`.


ABCD is a parallelogram.E is the mid-point of CD and P is a point on AC such that PC = `(1)/(4)"AC"`. EP produced meets BC at F. Prove that: 2EF = BD.


The figure obtained by joining the mid-points of the sides of a rhombus, taken in order, is ______.


In ∆ABC, AB = 5 cm, BC = 8 cm and CA = 7 cm. If D and E are respectively the mid-points of AB and BC, determine the length of DE.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×